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Citrus2011 [14]
3 years ago
13

What is X? x-3.9=12.4

Mathematics
1 answer:
valentinak56 [21]3 years ago
4 0

Answer:

Its 8.5

Step-by-step explanation:

I calculator

12.4+-3.9=8.5

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What is exactly the relation between a Rhombus, rectangle, parallelogram, and square explain please i will mark brainliest only
ch4aika [34]

Any rhombus is a parallelogram, but not the other way around. If you were to make a Venn Diagram, the "rhombus" portion is entirely inside the set of "parallelograms".

The same can be said about rectangles as well. Any rectangle is a parallelogram, but not the other way around.

If we overlapped the region of rectangles and rhombuses, then we form the region for squares. A square is a combination of a rhombus and a rectangle.

Any square has all four sides the same length (property of a rhombus) and all angles equal to 90 (property of a rectangle). Since a square inherits properties of a rectangle and rhombus, it automatically makes any square a parallelogram.

Check out the venn diagram below.

5 0
2 years ago
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What is the solution to log2(2x°-8)– 2log2x = log2x?
Butoxors [25]
Ima be honest I don’t know this one
3 0
3 years ago
What is the measure of angle BDC?
serious [3.7K]

Answer:

Like the angles BAC (56°) and BDC has the same arc BC in the circumference, these angles must be congruent, then angle BDC must be equal to 56°.

7 0
3 years ago
2. find C<br> Show exact steps used to solve
torisob [31]

Answer:

C=63.5

Step-by-step explanation:

3 0
2 years ago
A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte
puteri [66]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

\angle SPR=7.1^0=Angle subtended by the statue to where you are standing.

\angle x=\angleRPQ which is unknown.

Let us begin solving now. The first step is to find the angle \angle x which can be found by using the following trigonometric ratio in \Delta PQR:

tan(x)=\frac{RQ}{PQ}=\frac{21}{57}

Which gives x to be:

x=tan^{-1} (\frac{21}{57})\approx 20.22^{0}

Now, we know that \angle x and \angle SPR will get added to give us the complete angle \angle SPQ in the right triangle \Delta PQS.

We can again use the tan trigonometric ratio in \Delta PQS to solve for the height of the statue, h.

This can be done as:

tan(\angle SPQ)=\frac{SQ}{PQ}

tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}

tan(27.32^0)=\frac{h+21}{57}

\therefore h+21=57\times tan(27.32^0)

h\approx8.45 feet

Thus, the height of the statue is approximately, 8.45 feet.

5 0
3 years ago
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