Answer:
(-infinity, 0)
(0, 4]
[30, infinity)
Step-by-step explanation:
The inequality seems a little weird since it doesn't reflect the formula for speed accurately. The right inequality should be:
average speed >= 24
(first half speed + second half speed)/2 >= 24
(x+ (x-10))/2 >= 24
x-5>=24
x>= 29
In this case, the answer should be only [30, infinity)
If I solve the inequality given by the problems, the result will be:
1/x + 1/ (x-10) >= 2/24 ---> multiply both side with x(x-10)
x-10 + x >= (2x^2-20x)/24 ---> move /24 to left side
48x-240 >= 2x^2-20x ---> move all left side to right side
0>=2x^2 -68x+240 ---> divide both side by 2
0>=x^2 - 34x +120
0>=x^2-30x -4x+120
x(x-30) -4 (x-30)
(x-4) (x-30)
x1=4 x2=30
Since the coefficient of x^2 is positive so only area between two result is negative.
The answer will be
x1= (-infinity, 4]
x1= (-infinity, 0) , (0, 4]
x2= [30, infinity)
Hello! If you look at your gallon man, you see that 4 cups = 1 quart. Therefore, we can divide 56 cups by 4 to get the amount of quarts equivalent to 56 cups. 56/4 is 14. There. 56 cups = 14 quarts.
Answer:
The maximum profit is when they make 10 units of A and 2 units of B.
Step-by-step explanation:
Let x is units of milk
Let y units of cacao
Given that :
The company's production plant has a total of 22 units of milk and 46 units of cacao available.
2x + y ≤ 22 (2 unit of milk for each of A and 1 for B; 22 units available)
4x + 3y ≤46 (4 unit of milk for each of A and 3 for B; 46 units available
Graph the constraint equations and find the point of intersection to determine the feasibility region.
The intersection point (algebraically, or from the graph) is (10, 2)
The objective function for the problem is the total profit, which is $6.2 per unit for A and $4.2 per unit for B: 6.2x + 4.2y.
Hence, we substitute (10, 2) into the above function:
6.2*10 + 4.2*2 = 70.4
The maximum profit is when they make 10 units of A and 2 units of B.
The answer is 108' because if you add 35+1 all you have to do is multiply that times 3 which is 36'×3=108'
Answer:
the months would be the x axis and the numbers would be the y axis and the increments could start at 45k and have to go up to 800k don't forget the years with the months
