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2 years ago

What is the answer? please help

Mathematics

2 answers:

amid [387]2 years ago

7 0

Answer:

solution,

A(2,7)---------> (X1,y1)

B(6,3)--------->(x2,y2)

now,

 $ab = ( \frac{x1 + x1}{2} \: , \frac{y1 + y2}{2} ) \\ = (\frac{2 + 6}{2} \: , \frac{7 + 3}{2} ) \\ = ( \frac{8}{2} \:, \frac{10}{2} ) \\ = (4 ,\: 5)$ 

hope this helps...

Good luck on your assignment...

Virty [35]2 years ago

3 0

Answer:

Mp = (4 ; 5)

Step-by-step explanation:

Mp = [(Xa + Xb)/2 ; (Ya + Yb)/2]

= [(2+6)/2 ; (7+3)/2]

= (8/2 ; 10/2)

= (4 ; 5)

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2 years ago

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Strike441 [17]

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2 years ago

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Which represents the solution(s) of the graphed system of equations, y = x2 – 2x and y = –2x – 1? (1, –1) (0, 0) and (0, –1) (0,

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ANSWER

No solution

EXPLANATION

The first equation is

$y = {x}^{2} - 2x$

and the second equation is

$y = - 2x - 1$

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${x}^{2} - 2x = - 2x - 1$

This implies that

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${x}^{2} = - 1$

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3 years ago

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If John has pairs of red, orange, yellow, blue and green socks, how many can he wear them in over 5 days, repetition is allowed

iren [92.7K]

Answer:

Total ways = 5×5×5×5×5

Total ways = 5^5

Total ways = 3125

Therefore, the correct option is C) 5^5

Step-by-step explanation:

John has pairs of red, orange, yellow, blue and green socks.

Which means that John has 5 different colors pairs of socks.

We are asked to find out in how many ways can he wear them over 5 days.

1st Day:

On the first day John has 5 ways to choose from.

2nd Day:

On the second day John has 5×5 ways to choose from.

(Since repetition is allowed)

3rd Day:

On the third day John has 5×5×5 ways to choose from.

4th Day:

On the fourth day John has 5×5×5×5 ways to choose from.

5th Day:

On the fifth day John has 5×5×5×5×5 ways to choose from.

Total ways = 5×5×5×5×5

Total ways = 5^5

Total ways = 3125

Therefore, the correct option is C) 5^5

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3 years ago

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Answer:

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