Ask question

Ask question

All categories

3 years ago

15

Find the arc length of the curve

%7B1%7D%7B4%7D%20y%20%7B%20-%202%7D" id="TexFormula1" title="x = \frac{1}{8} y {4} + \frac{1}{4} y { - 2}" alt="x = \frac{1}{8} y {4} + \frac{1}{4} y { - 2}" align="absmiddle" class="latex-formula">
from y = 1 to y = 4.

1 answer:

vfiekz [6]3 years ago

8 0

Answer:x=2

Step-by-step explanation:

You might be interested in

Find the area of the triangle

Ray Of Light [21]

For this questions you need to memorize formula of triangle area. for question 5, just substitute the value into the formula. for Q6 you need to use pythagorean theorem formula to find the lenght of each triangle that i already seperated

4 0

3 years ago

What is 17 1/3 x 8 and how much water will each group get

stealth61 [152]

Answer:

The Answer to 17 1/3 x 8 is 138.67

There is not enough context to answer the second question.

8 0

3 years ago

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

$A=\sqrt{s(s-a)(s-b)(s-c)}$ , where $a$ , $b$ , and $c$ are three sides of the triangle and $s$ is the semi-perimeter ( $s=\frac{a+b+c}{2}$ ).

The semi-perimeter, $s$ , is:

$s=\frac{5+5+4}{2}=\frac{14}{2}=7$

Therefore, the area of the isosceles triangle is:

$A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}$

Thus, the area of the quadrilateral is:

$6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}$

4 0

3 years ago

The following data set shows the number of children in each household in Cam's neighborhood.

Anni [7]

Answer:

0

Step-by-step explanation:

The answer is 0. It shows up the most on the list. Also I know the awful Khan Academy brought you here.

8 0

3 years ago

Help me in number 8 plzz

Karo-lina-s [1.5K]

8a) The monthly rainfall is 3.6

8b) Deviation for May is 1
Deviation for June is 2.725
Deviation for July is 0.65

8c) Yes, the average annual rainfall was exceeded by 0.525

Please give me a rating if this helped

5 0

3 years ago