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LiRa [457]
3 years ago
15

Find the arc length of the curve

%7B1%7D%7B4%7D%20y%20%7B%20-%202%7D" id="TexFormula1" title="x = \frac{1}{8} y {4} + \frac{1}{4} y { - 2}" alt="x = \frac{1}{8} y {4} + \frac{1}{4} y { - 2}" align="absmiddle" class="latex-formula">
from y = 1 to y = 4.​
Mathematics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:x=2

Step-by-step explanation:

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Morgarella [4.7K]
Divide 30/1.4 and 436.60 should give uu how much he makes in his normal hourly rate multiply that by 5 and subtract that number from 436.60
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Select the correct answer.
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5 0
3 years ago
The school chorus has 52 students which represents 26% of the seventh graders. How many students are in the seventh grade
barxatty [35]

Answer:

There are 200 students in the seventh grade.

Step-by-step explanation:

For equations like these, you have to use the is/of formula, which is:

Percent/100 = is/of.

Since you are trying to find how many students are in the seventh grade, this means that 52 <u><em>is</em></u> 26% of the total amount of students in the seventh grade. So, the formula would look like so:

26/100 = 52/n.

Next, you have to cross multiply, which means you would multiply 26 by n, and 52 by 100.

Then, you are going to have this left over from the cross multiplying:

5200 = 26n.

Divide 26 on both sides, leaving you with:

1n = 200, or n = 200.


8 0
3 years ago
Why will the value of y for the function y equals 5x + 1 always be greater than that of y equals 4x + 1 with X greater than 1?
klemol [59]
You mean
the linear equations, 5x-y+1=0,4x-y+1=0
the slopes are 5 and 4 respectively.
it is clear that slope of first equation is greater that is it has a steeper graph therefore it Will always be greater than the other for x > 1
the same can be done by calculus; differentiation.

note y=5x+1 is always greater than y=4x+1 for all x>1
4 0
3 years ago
Read 2 more answers
Question part points submissions used solve the given differential equation by separation of variables. dx + e2xdy = 0
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Try this:
if given dx+e²ˣdy=0, then
dy=- \frac{dx}{e^{-2x}} \ =\ \textgreater \  \  \int dy=-\int e^{-2x}dx; \ =\ \textgreater \  \ y= \frac{1}{2}e^{-2x}+C;
4 0
3 years ago
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