Let S be the sum,
S = 2 + 4 + 6 + ... + 2 (n - 2) + 2 (n - 1) + 2n
Reverse the order of terms:
S = 2n + 2 (n - 1) + 2 (n - 2) + ... + 6 + 4 + 2
Add up terms in the same positions, so that twice the sum is
2S = (2n + 2) + (2n + 2) + (2n + 2) + ... + (2n + 2)
or
2S = n (2n + 2)
Divide both sides by 2 to solve for S :
S = n (n + 1)
12x1
12x2
12x3
12x4
12x5
12x6
12x7
12x8
12x9
12x10
Answer:
294 square units
Step-by-step explanation:
35^2-21^2=a^2
a^2=784
square root 784=28
21*28/2=294
Answer=294
Answer:
14694
Step-by-step explanation:
Answer:
The Answer Would Be C. A'(-5, -5), B'(-5, -1). C'(-2,-1).
D(5, -1)
Quick math. ;)