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slavikrds [6]
3 years ago
8

Shelly can cut a lawn with a riding mower in 22 hours less time than it takes william to cut the lawn with a push mower. if they

can cut the lawn in 33 hours working together find how long to the nearest tenth of an hour it takes for william to cut the lawn alone.
Mathematics
1 answer:
umka2103 [35]3 years ago
7 0
Let n be the amount of time it takes william to cut the lawn. Then Shelly takes
n-2 hours. So:
1/n+1/n-2=1/3
3(n-2)+3n=n²-2n
6n-6=n²-2n
n²-8n+6=0
Using the quadratic formula, we get a positive value of 7.1623 hrs as the amount of time william takes working alone, and 5.1623 as the amount  of time Shelly takes working alone
☺☺☺☺
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The area needed is at least 170.5 ft².

Let w  =  the width of the rectangular area.
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3 years ago
Calculate the average rate of change over the interval 2
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Answer:

Average rate of change over the interval 2<= x <= 5:

y = 3x + 5:        3

y = 3x^2 + 1:     21

y = 3^x:             78

<u />

Step-by-step explanation:

2<= x <= 5

Average rate of change over the interval 2<= x <= 5:

<u>y = 3x + 5</u>

y(5) = 3(5) + 5 = 20

y(2) = 3(2) + 5 = 11

Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>

<u />

<u>y = 3x^2 + 1</u>

y(5) = 3(5^2) + 1 = 75 + 1 = 76

y(2) = 3(2^2) + 1= 13

Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>

<u />

<u>y = 3^x</u>

y(5) = 3^5 = 243

y(2) = 3^2 =9

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Step-by-step explanation:

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Step-by-step explanation:

B' stands for the complement of B.

B' means set elements in the universe that aren't in B.

Here is the universe:

U={1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,...}

(The dots mean it continues with that pattern forever and ever.)

And the elements we taking out:

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