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Viktor [21]
3 years ago
15

Digestive enzymes in your stomach and intestines help digest the food you eat. If you are lactose intolerant and cannot digest m

ilk
products, it is the result of a mutated message in your
Biology
2 answers:
storchak [24]3 years ago
6 0

Answer:

Lactose intolerance is when your body can't break down or digest lactose. Lactose is a sugar found in milk and milk products. Lactose intolerance happens when your small intestine does not make enough of a digestive enzyme called lactase. Lactase breaks down the lactose in food so your body can absorb it.

Explanation:

BigorU [14]3 years ago
4 0

Answer:

It is the result of a mutated message in your chromosomes. Chromosomes do not just determine how you look but they control all the processes of the cells in an organism.

You might be interested in
The histone proteins are among the most slowly evolving proteins. For example, a histone protein called histone H4 in cows and p
juin [17]

The statement is true, histones are proteins that are high in the amino acids lysine and arginine, making them extremely basic in their structure.

Histones control the degree of packaging of DNA during the processes of gene expression, replication or repair of hereditary material, among many others.

Histones H2A, H2B, H3 and H4 are small and basic proteins that are highly conserved in evolution and are composed of a globular domain at the carboxy-end, and by regions known as "tails", which are found at the amino-terminal end.

These tails are high in the amino acids lysine and arginine, which give them a positive charge.

This region is the site of numerous post-translational modifications that, it has been proposed, would modify the histone charge, altering the accessibility of the DNA and the protein / protein interactions with the nucleosome.

Chromatin compaction occurs due to the interaction between the negative charges of DNA and the positive charges of amino acids, mainly located on the tails of histones H3 and H4.

Therefore, we can conclude that the modifications on the amino acids lysine and arginine that form the basic part of the histone structure alter their functions.

Learn more about histone proteins here: brainly.com/question/14984828

8 0
3 years ago
If two genes are found on different chromosomes, or if they are far enough apart on the same chromosome that the chance of a cro
nika2105 [10]

Complete question:

A wild-type tomato plant (Plant 1) is homozygous dominant for three traits: solid leaves (MM), normal height (DD), and smooth skin (PP).

Another tomato plant (Plant 2) is homozygous recessive for the same three traits: mottled leaves (mm), dwarf height(dd), and peach skin (pp).

In a cross between these two plants (MMDDPP x mmddpp), all offspring in the F1 generation are wild type and heterozygous for all three traits(MmDdPp).

Now suppose you perform a testcross on one of the F1plants (MmDdPp x mmddpp). The F2 generation can include plants with these eight possible phenotypes:

solid, normal, smooth

solid, normal, peach

solid, dwarf, smooth

solid, dwarf, peach

mottled, normal, smooth

mottled, normal, peach

mottled, dwarf, smooth

mottled, dwarf, peach

Assuming that the three genes undergo independent assortment, predict the phenotypic ratio of the offspring in the F2 generation.

Answer and Explanation:

<u>Cross 1:</u>

Parental) MMDDPP  x  mmddpp

F1) MmDdPp

<u>Cross 2</u>: <em>Testcross</em>

Parental) MmDdPp   x   mmddpp

Gametes) MDP   MdP   MDp  Mdp   mDP   mdP   mDp  mdp

                 mdp   mdp   mdp   mdp   mdp   mdp   mdp   mdp

Punnet Square)

              mdp            

MDP     MmDdPp

MdP     MmddPp

MDp     MmDdpp

Mdp     Mmddpp

mDP     mmDdPp

mdP     mmddPp

mDp     mmDdpp

mdp      mmddpp    

F2) 8/64 = 1/8 MmDdPp, solid leaves, normal height, smooth skin

     8/64 = 1/8 MmddPp,  solid leaves, dwarf height, smooth skin

     8/64 = 1/8 MmDdpp, solid leaves, normal height, peach skin

     8/64 = 1/8 Mmddpp,  solid leaves, dwarf height, peach skin

     8/64 = 1/8 mmDdPp, mottled leaves, normal height, smooth skin

     8/64 = 1/8  mmddPp,  mottled leaves, dwarf height, smooth skin

     8/64 = 1/8  mmDdpp,  mottled leaves, normal height, peach skin

     8/64 = 1/8  mmddpp,  mottled leaves, dwarf height, peach skin

Another way of predicting the phenotypic ratio of the offspring in the F2 generation is by performing a testcross for each gene by separately and then multiplying their genotypic proportions. This is:

<u><em>Leaves Gene</em></u>

Parental) Mm  x  mm

Gamtes) M  m    m   m

Punnet Square)        M     m

                       m    Mm   mm

                       m    Mm   mm

F2) 1/2 Mm

      1/2 mm

<u><em>High Gene</em></u>

Parental) Dd  x  dd

Gamtes) D  d    d   d

Punnet Square)       D     d

                       d     Dd    dd

                       d     Dd    dd

F2) 1/2 Dd

      1/2 dd

<u><em>Skin Gene </em></u>

Parental) Pp  x  pp

Gamtes) P   p   p   p

Punnet Square)       P    p

                          p   Pp   pp

                          p   Pp   pp

F2) 1/2 Pp

      1/2 pp

To get the phenotypic ratio of the offspring we multiply the genotypic proportion for each trait by the genotypic proportions of the other two traits, like this:

  • For plants with solid leaves, normal height, smooth skin

solid leaves ratio -> 1/2

normal height ratio -> 1/2

smooth skin ratio -> 1/2

MmDdPp ratio: 1/2 x 1/2 x 1/2 = 1/8

  • For plants with solid leaves, dwarf height, smooth skin

MmddPp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

  • For plants with solid leaves, normal height, peach skin

MmDdpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

  • For plants with solid leaves, dwarf height, peach skin

Mmddpp ratio:  1/2 x 1/2 x 1/2 x 1/2 = 1/8

  • For plants with mottled leaves, normal height, smooth skin

mmDdPp  ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8  

  • For plants with mottled leaves, dwarf height, smooth skin

mmddPp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8

  • For plants with mottled leaves, normal height, peach skin

mmDdpp ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8  

  • For plants with mottled leaves, dwarf height, peach skin

mmddpp  ratio: 1/2 x 1/2 x 1/2 x 1/2 = 1/8                    

3 0
3 years ago
A scientist examines the body fossil and trace fossils left by an
emmasim [6.3K]

Given what we know, we can confirm that as scientists study fossil records, they can learn much about the species, such as the traits and activities of the organisms in question.

<h3>What does each fossil type teach us?</h3>
  • Trace fossils such as footprints can teach us about the activities of the organisms.
  • Meanwhile, scientists will use body fossils to learn about the specific traits of early organisms.
  • Body fossils can at times also provide insight as to the diet of the species.

Therefore, we can confirm that scientists will use body fossils to learn more about the traits and diets of early organisms while using the uncovered trace fossils to track the activities of these organisms.

To learn more about fossils visit:

brainly.com/question/1241920?referrer=searchResults

7 0
3 years ago
Read 2 more answers
Traditionally, it is taught that the neuron is the functional unit of the nervous system. what do some neuroscientists suggest i
Rashid [163]
Neural networks, because even the most basic functions require circuits of neurons rather than just a single neuron.
5 0
3 years ago
Describe how the structure of a virus aids in its ability to infect cells.
Varvara68 [4.7K]

Virulence factors of virus aids in its ability to infect cells.  

Explanation:

Virulence factors help pathogenic microbes to infect host cells by virulence mechanisms – invade host, cause and spread disease, evade the defense or immune mechanism of the host. These factors makes the virus to grow, replicate, and modify the host cells due to its toxicity.  

Viruses binds to the receptor protein of the host cell.

Different types of virulent factors are: invasion factors, adhesive or adherent factors, capsules, endo and exotoxins, etc.  

The virulence factors decides the severity and rate of spread of an infection

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3 years ago
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