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3 years ago

Find the zeros with multiplicity for the function p(x) = (x^3 – 8)(x^5 – 4x^3)

1 answer:

5 0

X^3 - 8 = 0 Gives us a zero of x = 2

x^5 - 4x^3 = 0 gives another zero of x = 0

x^3(x^2 - 4) = 0 gives 2 more zeros (x^2 = 4 so x = 2, -2)

So the answer is -2, 0 and 2 multiplicity 2

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notsponge [240]

$\text{Hey there!}$

$\text{The midpoint formula is: }\dfrac{\mathsf{x_2+x_1}}{2}, \dfrac{\mathsf{y_2+y_1}}{2}$

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$\mathsf{x_1 = -1}\\\\\mathsf{x_2=2}\\\\\mathsf{y_1=4}\\\\\mathsf{y_2=2}$

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$\dfrac{2-1}{2}\\\\\mathsf{2-1 = 1}\\\\\mathsf{2=2}\\\\\\\mathsf{x = \dfrac{\mathsf{1}}{2}}$

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$\mathsf{\dfrac{4+2}{2}}\\\\\mathsf{4+2=6}\\\\\mathsf{2=2}\\\\\mathsf{\dfrac{6}{2}=3}\\\\\\\mathsf{y=3}$

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$\boxed{\boxed{\text{Thus,\ your\ answer\ is:\boxed{(\dfrac{1}{2\ },\ 3)}}}}\checkmark$

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$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

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3 years ago

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PolarNik [594]

1 1/4=5/4
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4 years ago

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elena55 [62]

Answer:

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Step-by-step explanation:

Mark ‼️ as brainlist ‼️❣️

hope you get ur answer

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allochka39001 [22]

I suggest drawing a graph or simply using a calculator

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;)

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