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abruzzese [7]
3 years ago
13

Help please really needed

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer:

the answer is C hope this helps

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If you can help that be great!​
muminat

the answer is B 2.75 miles per hour

7 0
3 years ago
M is the midpoint of AB.<br> AM = = 4x - 8<br> MB =<br> 5x-3/3<br> Find x and AB
marusya05 [52]
X=-7 AB=-72

steps

since m is a midpoint, AM and MB are congruent so you set the two equations equal to each other, 4x-9=5x-3/3( is this a typo? bc 3/3 is 1)
subtract 4x from both sides m, -8=x-1
add 1 to both sides
x=-7

then plug -7 in for x 4(-7)-8=-36
since the two segments are congruent u do -36 x 2= -72
7 0
3 years ago
What does 2n − 3x equally to
DIA [1.3K]

Answer:

2÷45 - 76<em><u> </u></em><em><u>and </u></em><em><u>the </u></em><em><u>answer </u></em><em><u>is </u></em><em><u>yours</u></em>

5 0
3 years ago
Identify the function shown in this graph.
jolli1 [7]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A certain circle can be represented by the following equation. x^2+y^2+6y-72=0 What is the center of this circle ?
jek_recluse [69]

Answer:

(0, -3)

Step-by-step explanation:

Here we'll rewrite x^2+y^2+6y-72=0 using "completing the square."

Rearranging x^2+y^2+6y-72=0, we get  x^2 + y^2 + 6y                = 72.

x^2 is already a perfect square.  Focus on rewriting y^2 + 6y as the square of a binomial:  y^2 + 6y becomes a perfect square if we add 9 and then subtract 9:

x^2 + y^2 + 6y + 9  - 9              = 72:

x^2 + (y + 3)^2 = 81

Comparing this to the standard equation of a circle with center at (h, k) and radius r,

(x - h)^2 + (y - k)^2 = r^2.  Then h = 0, k = -3 and r = 9.

The center of the circle is (h, k), or (0, -3).

8 0
3 years ago
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