An integer may be a multiple of 3.
An integer may be 1 greater than a multiple of 3.
An integer may be 2 greater than a multiple of 3.
It is redundant to say an integer is 3 greater than a multiple of 3 (that's just a multiple of 3, we've got it covered). Same for 4, 5, 6, 7...
Let's consider a number which is a multiple of 3. Clearly, we can write 3+3+3+3+... until we reach the number. It can be written as only 3's.
Let's consider a number which is 2 greater than a multiple of 3. If we subtract 5 from that number, it'll be a multiple of 3. That means we can write the number as 5+3+3+3+3+... Of course, the number must be at least 8.
Let's consider a number which is 1 greater than a multiple of 3. If we subtract 5 from that number, it'll be 2 greater than a multiple of 3. If we subtract another 5, it'll be a multiple of 3. That means we can write the number as 5+5+3+3+3+3+... Of course, the number must be at least 13.
That's it. We considered all the numbers. We forgot 9, 10, 11, and 12, but these are easy peasy.
Beautiful question.
Answer:
C
Step-by-step explanation:
area is pi X radius squared
radius is half of diameter
so it is pi X 6²
wich is pi X 36
Answer:
Please check the explanation.
Step-by-step explanation:
Given the sequence
2, 6, 10, 14, 18
An arithmetic sequence has a constant difference and is defined as
compute the differences of all the adjacent terms
The difference between all the adjacent terms is the same.
Thus,
and
Therefore, the nth term is computed by:
Thus, position to term rule of 2, 6, 10, 14, 18 multiply by __4___ and subtract by __2__.
32/36=8/9 divided both digits by 4