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Luba_88 [7]
3 years ago
9

Pls helpASAP!!! 3x+ 12 = 2(8+ 4x)

Mathematics
2 answers:
mojhsa [17]3 years ago
5 0

3x+12=2(8+4x) distribute

3x+12=16+8x\\ collect like-terms

3x-8x=16-12\\-5x=4\\x=-\frac{4}{5}=-0.8

Tems11 [23]3 years ago
4 0
  • Answer:

<em>x = - 4/5</em>

  • Step-by-step explanation:

<em>3x + 12 = 2(8 + 4x)</em>

<em>3x + 12 = 16 + 8x</em>

<em>12 - 16 = 8x - 3x</em>

<em>- 4 = 5x</em>

<em>x = - 4/5</em>

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3 years ago
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Step-by-step explanation:

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8 0
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3 0
3 years ago
X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square
swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = -\frac{4}{5}x+\frac{58}{5}

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

   [x² + 2(2)x + 4] - 4 + [y² - 2(5)y + 25] - 25 + 20 = 30

   (x + 2)² + (y - 5)²- 29 + 20 = 30

   (x + 2)² + (y - 5)²- 9 = 30

   (x + 2)² + (y - 5)² = 39

By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{10-5}{2+2}

          = \frac{5}{4}

    Let the slope of the tangent which is perpendicular to this line is 'm_{2}'

    Then by the property of perpendicular lines,

          m_{1}\times m_{2}=-1

          \frac{5}{4}\times m_{2}=-1

                 m_{2}=-\frac{4}{5}

   Now the equation of the line passing though (2, 10) having slope m_{2}=-\frac{4}{5}

           y - y' = m_{2}(x-x')

           y - 10 = -\frac{4}{5}(x-2)

           y - 10 = -\frac{4}{5}x+\frac{8}{5}

                  y = -\frac{4}{5}x+\frac{8}{5}+10

                  y = -\frac{4}{5}x+\frac{58}{5}

Therefore, equation of the line will be, y = -\frac{4}{5}x+\frac{58}{5}

7 0
3 years ago
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