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Vlad [161]
3 years ago
11

PLEASE HELP ME ONLY THE NICEST PERSON WILL HELP ME. :(

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0
Where’s the second paragraph?
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Can some help ...:.....0
frozen [14]

Answer:

-4

Step-by-step explanation:

Two legs of the triangle are congruent as shown by the tick marks. This means that this is an isosceles triangle; in an isosceles triangle, the two base angles are also congruent. Which means <A and <B are congruent.

So to solve for x, set 28 and 10x+68 equal to each other.

28=10x+68

First, subtract 68 from both sides

-40=10x

Then, divide both sides by 10

-4=x

If you want to check your answer plug -4 back into the original equation.

28=10(-4)+68

28=-40+68

28=28, which is true, therefore -4 is correct.

7 0
3 years ago
How do you solve -3x+28=10
Anna [14]

Answer: x = 6

Step-by-step explanation: To solve for <em>x</em>, we must first isolate the term containing <em>x</em> which in this problem is -3x.

Since 28 is being added to -3x, we subtract 28 from both sides of the equation to isolate the -3x. On the left, the +28 and -28 cancel out and on the right 10 - 28 is -18 so we have -3x = -18.

Now we can finish things off by just dividing both sides of the equation by -3. On the left the -3's cancel and we have <em>x</em>. On the right, -18 divided by -3 is 6 so we have x = 6 which is the solution to our equation.

6 0
3 years ago
Read 2 more answers
Which of the following reveals the minimum value for the equation 3x2 + 18x + 15 = 0?
11111nata11111 [884]

Answer:

Step-by-step explanation:

I have no idea

7 0
3 years ago
What is the answer to this 1.84 × 25.1
kykrilka [37]

The answer to 1.84 x 25.1 is 46.184. Hope this helped.

4 0
3 years ago
Danielle borrowed $125 to pay for school books. She needs to pay it back with interest in 2 years. Danielle wants to figure out
Gemiola [76]

Answer:

<h2>Rate</h2>

Step-by-step explanation:

Danielle has :

Principal = $125

Time = 2 years

Rate = ?

Interest =

\frac{Principal  \times Rate \times Time}{100}

6 0
3 years ago
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