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Dafna1 [17]
3 years ago
13

Suppose you record how long it takes you to get to school over many months and discover that the one-way travel times, in minute

s, are approximately normally distributed with a mean of 13.88 minutes and standard deviation of 4 minutes. you are interested in the probability that it will take you at least 20 minutes to get to school

Mathematics
1 answer:
Lemur [1.5K]3 years ago
4 0
The probability it will take 20 minutes or more is about 6.3%.

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A real estate sales agent receives a salary of $250 per week plus a commission of 2% of sales.Write an equation that gives the w
lisabon 2012 [21]

The equation y=0.02x+250 gives the weekly income y in terms of sales x.

Step-by-step explanation:

Given,

Weekly salary of real estate agent = $250

Commission rate = 2%

Let,

x be the sales per week.

y be the total weekly income.

Amount of commission = 2% of sales per week

Amount of commission = \frac{2}{100}*x

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The equation y=0.02x+250 gives the weekly income y in terms of sales x.

Keywords: equation, percentage

Learn more about percentages at:

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3 0
4 years ago
What is a independent event
Andreas93 [3]

Step-by-step explanation: If two events are independent events, then the outcome of one event will not affect the outcome of the other event. I'll show an example.

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This problem would be dealing with independent events because the outcome of tossing 1 coin does not affect the outcome of tossing the second coin.

4 0
3 years ago
What is the solution for
sveticcg [70]

Answer:

The answer is letter B.

8 0
4 years ago
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<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2
PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

\large\underline{\sf{Solution-}}

Given Trigonometric expression is

\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }

So, on rationalizing the denominator, we get

\rm \:  =  \: \dfrac{sin\theta }{1 + cos\theta }  \times \dfrac{1 - cos\theta }{1 - cos\theta }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) =  {x}^{2} -  {y}^{2} \: }}}

So, using this, we get

\rm \:  =  \: \dfrac{sin\theta (1  -  cos\theta )}{1 -  {cos}^{2}\theta  }

We know,

\purple{\rm :\longmapsto\:\boxed{\tt{  {sin}^{2}x +  {cos}^{2}x = 1}}}

So, using this identity, we get

\rm \:  =  \: \dfrac{sin\theta (1 -  cos\theta )}{{sin}^{2}\theta  }

\rm \:  =  \: \dfrac{1 - cos\theta }{sin\theta }

<u>Hence, </u>

\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta }   =  \: \dfrac{1 - cos\theta }{sin\theta } }}} \\

3 0
3 years ago
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