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lara [203]
3 years ago
13

(1) Cos AcosecA=cot A​

Mathematics
1 answer:
Mashutka [201]3 years ago
7 0

Answer:

The Basic Identities are :

cosec(A) =  \frac{1}{ \sin(A) }

\tan(A)  =  \frac{ \sin(A) }{ \cos(A) }

\cot(A)  =  \frac{1}{ \tan(A) }  =  \frac{ \cos(A) }{ \sin(A) }

So for this question :

\cos(A)cosec(A) =  \cot(A)

l.s.h =  \cos(A)  \times  \frac{1}{ \sin(A) }

l.s.h =  \frac{ \cos(A) }{ \sin(A) }

l.sh =  \cot(A)  \: (proven)

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How to find a tangent ratio
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The tangent ratio is the value received when the length of the side opposite of angle theta is divided by the length of the side adjacent to angle theta. It is very commonly abbreviated as tan.

4 0
3 years ago
1. Many Alpine ski centers base their calculations of revenues and profits on the belief that the average skier ski’s four times
pshichka [43]

Answer:

We cannot infer at the 10% significance level that the assumption of ski centers is wrong

Step-by-step explanation:

The null hypothesis for this question can be stated as  

Null hypothesis H0:  =4  

Alternate hypothesis Ha:  

The test is two tailed

Standard Deviation –  

 = 2

z=(4.84-4)/(2/sqrt(63))

=3.33

Z(0.1/2)=1.645 is less than Z =3.334

Hence, we will reject H0  

Hence, the average growth skier ski’s four times a year is not true  

6 0
2 years ago
Jasper wants to buy a video game that costs $35. He has $10.50, and his weekly allowance is $5. If w represents the number of we
Ksju [112]

Answer:

He would have to wait for 5 weeks

Step-by-step explanation:

$5 x $5 = $25

$25 + $10.50 = $35.50

6 0
3 years ago
Read 2 more answers
There were 324 adults surveyed. Among the participants, the mean number of hours of sleep each night was 7. 5 and the standard d
NeTakaya

The margin of error for 324 adults surveyed with 1.6 standard deviations is 0.1742.

<h3>What is the margin of error?</h3>

The margin of error can be defined as the amount of random sampling error in the results of a survey. It is given by the formula,

\text{MOE}_{\gamma}=z_{\gamma} \times \sqrt{\frac{\sigma^{2}}{n}}

\text{MOE} = margin of error

\gamma = confidence level

z_{\gamma} = quantile

σ = standard deviation

n = sample size

As it is given that the sample size of the survey is 324, while the standard deviation of the survey is 1.6.

We know that the value of the z for 95% confidence interval is 1.96. Therefore, using the formula of the standard of error we can write it as,

\text{MOE}_{\gamma}=z_{\gamma} \times \sqrt{\dfrac{\sigma^{2}}{n}}\\\\\text{MOE}_{\gamma}=1.96 \times \sqrt{\dfrac{1.6^{2}}{324}}\\\\\text{MOE}_{\gamma}=0.1742

Hence, the margin of error for 324 adults surveyed with 1.6 standard deviations is 0.1742.

Learn more about Margin of Error:

brainly.com/question/6979326

5 0
2 years ago
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