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lara [203]
3 years ago
13

(1) Cos AcosecA=cot A​

Mathematics
1 answer:
Mashutka [201]3 years ago
7 0

Answer:

The Basic Identities are :

cosec(A) =  \frac{1}{ \sin(A) }

\tan(A)  =  \frac{ \sin(A) }{ \cos(A) }

\cot(A)  =  \frac{1}{ \tan(A) }  =  \frac{ \cos(A) }{ \sin(A) }

So for this question :

\cos(A)cosec(A) =  \cot(A)

l.s.h =  \cos(A)  \times  \frac{1}{ \sin(A) }

l.s.h =  \frac{ \cos(A) }{ \sin(A) }

l.sh =  \cot(A)  \: (proven)

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In the 30-60-90 triangle below, side s has a length of _ and side q has a length of _.
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Answer: F

Step-by-step explanation:

For a 30-60-90 triangle, we know that the hypotenuse is 2x. Since we know the hypotenuse is 10, we can solve for x.

2x=10

x=5

Now that we know x is 5, we can use this to solve for s and q. The side across from 30° is just x. Since we know x, s is 5.

The side across from 60° is x√3. Since we know what x is, we can just plug in. q is 5√3.

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Solve the equation x³ - 5x²+2x+8 = 0 given that - 1 is a zero of f(x)= x3 - 5x²+2x+8.
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added in the picture

Step-by-step explanation:

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3 0
2 years ago
-7πh = 98π <br> solve for h
ICE Princess25 [194]

Answer:

h = -14

Step-by-step explanation:

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⇔ h = 98 ÷ (-7) = -14

5 0
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