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slamgirl [31]
4 years ago
8

A tank can be filled by one pump in 3.2 hours and by another pump in 80 minutes. A third pump can drain the tank in 2 hours and

20 minutes. If all 3 pumps go into operation, how long will it take to fill the tank?
Mathematics
1 answer:
Mademuasel [1]4 years ago
6 0

Answer:

Rounding to the nearest minute, it would take 95 minutes, or 1 hour and 35 minutes.

Step-by-step explanation:

Let's convert each time to minutes:

3.2 hours = 192 minutes

80 minutes = 80 minutes

2 hr 20 min = 140 minutes

Next, let's find the least common multiple:

LCM(192, 80, 140) = 6720

So let's say the volume of the tank is 6720 units.  The speed of each pump is therefore:

Pump 1 = 6720 units / 192 minutes = 35 units/minute

Pump 2 = 6720 units / 80 minutes = 84 units/minute

Pump 3 = -6720 units / 140 minutes = -48 units/minute

Their combined speed is:

35 + 84 − 48 = 71 units/minute

So the time to fill the tank is:

6720 units / (71 units/minute) = 94.65 minutes

Rounding to the nearest minute, it would take 95 minutes, or 1 hour and 35 minutes.

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Answer: Jack has $42

Step-by-step explanation:

Let be "j" the amount of money in dollars that Jack has, "w"  the amount of money in dollars that Walker has and "t"  the amount of money in dollars that Trust has.

You know that they have $100 altogether, then you can write the following equation:

j+w+t=100   [Equation 1]

Jack has $20 more than Walker, then:

j=w+20      [Equation 2]

And  Trust has $14 more than walker, then you can write this equation:

t=w+14      [Equation 3]

Substitute the  Equation 2 and the  Equation 2 into the first one:

j+w+t=100\\\\(w+20)+w+(w+14)=100

Now, solve fo "w":

w+20+w+w+14=100\\\\3w+34=100\\\\3w=100-34\\\\w=\frac{66}{3}\\\\w=22

Finally, substiute the value of "w" into the Equation 2 and evaluate:

j=w+20\\\\j=22+20\\\\j=42

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