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Naily [24]
3 years ago
7

Solve please -3x-27=

Mathematics
2 answers:
juin [17]3 years ago
6 0

Answer:

−3(x+9)

Step-by-step explanation:

murzikaleks [220]3 years ago
5 0
The answer is -3(x-27)
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Point E is where the statue should be placed.

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At what point should the statue be:

The intersection of the doors to the arena, the spirit store, and the parking lot forms a triangle, with Point E in its center. The radius of the circumscribed circle will therefore equal the distance from the statue to each vertex, placing it at the same distance from all three landmarks.

Point E is where the statue should be placed.

To learn more about the Triangle, refer to:

brainly.com/question/17335144

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2 years ago
A Hindu might try to live a virtuous life to _____________.
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The answer is B. Hindus believe in the concept of reincarnation, so obtaining good karma by living a virtuous life will help a person to be reborn of a higher caste (a higher position in the social order)  in their next life.
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4 years ago
Jake has proved that a function, f(x), is a geometric sequence. How did he prove that?
Mashutka [201]

Answer:

He showed that f(n) ÷ f(n - 1) was a constant ratio.

Given that Jake has proved that a function f(x) is a geometric sequence.

GEOMETRIC SEQUENCE:  A geometric sequence is a sequence of numbers where each term is found by multiplying the preceding term by a constant called the common ratio, r.

So, in Jame's proof, he showed that each term is multiplied by a constant to get the next term.

That is, if 'c' is the constant that was used in the proof, then we must have

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if you take out a loan that cost $130.50 over 9 years and interest rate of 10% how much total was the loan for
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3 years ago
Find a unit vector that is orthogonal to both i + j and i + k.
kenny6666 [7]

Answer: i - j - k

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Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.

<1,1,0> x <1,0,1>

det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )

the determinate of the matrix: <1,-(1),-1>

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