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2 years ago

Which function has real zeros at x = 3 and x = 7?

Mathematics

2 answers:

inna [77]2 years ago

8 0

Answer:

C. f(x) = x2 – 10x + 21

Step-by-step explanation:

AlexFokin [52]2 years ago

5 0

Hello,

Answer C
s=3+7=10
p=3*7=21
==>x²-10x+21

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If the hypotenuse of a right triangle has length 9 feet and one of the other sides has length 2 feet, what is the length of the

alex41 [277]

Hypotenuse=H=9ft
Base=B=2ft

Apply Pythagorean theorem

P²=H²-B²
P²=9²-2²
P²=81-4
P²=77
P=√77

Option D

4 0

1 year ago

Read 2 more answers

If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn

mash [69]

Let $a=\tan A$ and $b=\sin A$ . Then

$m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab$

$\implies m^2-n^2=4\tan A\sin A$

and

$mn=(a+b)(a-b)=a^2-b^2$

$\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}$

The expression under the square root can be rewritten as

$\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)$

Recall that

$\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A$

so that

$\tan^2A-\sin^2A=\sin^2A\tan^2A$

and assuming $\sin A>0$ and $\tan A>0$ , we end up with

$4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A$

so that

$m^2-n^2=4\sqrt{mn}$

as required.

5 0

2 years ago

A staircase has an angle of elevation of 28° anı

AveGali [126]

Hi there!

We can use right-triangle trigonometry to solve.

We are given the HYPOTENUSE and ADJACENT sides, so we must use cosine in this instance.

cosθ = Adjacent/Hypotenuse

We can plug in what is given:

cos(28) = A/17

Solve for 'A':

17cos(28) = <u>15.01 ft</u>

5 0

2 years ago

A line perpendicular to the line y=5x+6

Ratling [72]

Answer:

y= -10x +12

Step-by-step explanation:

3 0

2 years ago

What compound inequality describes the graph shown below?

NARA [144]

Answer is less than or equal to -7 or -5greater than or equal to

4 0

2 years ago