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JulsSmile [24]
3 years ago
8

PLZ HELP IM TIMMED The following sets of numbers are possible side lengths of a triangle. Which of the following sets forms a Py

thagorean triple?
18, 24, 42
45, 28, 53
15, 30, 45
33, 77, 22
Mathematics
2 answers:
Serggg [28]3 years ago
4 0

Answer:

Test each set of lengths using Pythagoras' Theorem. Is a2+b2=c2?

Step-by-step explanation:

erma4kov [3.2K]3 years ago
4 0

Answer:

You have to see each one and do the formula, a^2*b^2= c^2, then under'root the c^2 to become c

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If f(x) = 2x + 6 and g(x) = -4x - 8 find f(g(x)) = ?x+?
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3 years ago
In a certain city, there are about one million eligible voters. A simple random sample of size 10,000 was chosen to study the re
Ronch [10]

Answer:

REQUIRED TEST STATICS IS 35.19

Step-by-step explanation:

total size of sample = 10,000

                                     men                            women

voted                           2777                            3466

did not vote                  1444                             2313

By chi square test we can find the relationship between gender and participation in the election

<em>X^2 = \frac{ N(ad-bc)^2}{(a+c)(b+d)+(a+b)(c+d)}</em>

where

a represent  = 2777, b = 3466, c= 1444, d = 2313, N = 10000

Putting values to get chis square statics

<em>X^2 = \frac{ 10000(2777*2313-3466*1444)^2}{(2777+1444)(3466+2313)+(2777+3466)(1444+2313)}</em>

<em>X^2 = = 35.159</em>

HENCE REQUIRED TEST STATICS IS 35.19

3 0
3 years ago
Simplify negative 8 over 3 divided by negative 2 over 6
Art [367]

Answer: The answer is 8

5 0
3 years ago
If the diameter of the circle is 6 cm, find its circumference. [Use 3.14 for π.] A) 18.84 cm B) 25.12 cm C) 37.68 cm D) 50.24 cm
agasfer [191]
Circumference = π * d

π=3.14
diameter = 6

3.14 * 6 = 18.84.
The answer is A.

Hope this helped☺☺
7 0
3 years ago
Read 2 more answers
What is the complete factorization of 36y2 − 1?
ludmilkaskok [199]

Answer:

36y² - 1

Factorize

We have the final answer as

(y -  \frac{1}{6} )(36y + 6)

Hope this helps you

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3 years ago
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