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myrzilka [38]
4 years ago
9

How do you factor 3x^2-7x-2

Mathematics
1 answer:
vivado [14]4 years ago
3 0

3x^2-7x-2

doesn't factor


You can not factor this


I hope that's help !

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balu736 [363]

Answer:

it is 6

Step-by-step explanation:

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3 years ago
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puteri [66]

Answer:

The salt concentration of the mixed solution = 10%

Step-by-step explanation:

First assuming that the concentration of salt given is on a vol% basis.

First solution has 0.7 gallon of 5% salt

Amount of salt in this solution = 5% × 0.7 = 0.035 gallon

Second solution has 0.3 gallon of 22% salt

Amount of salt in this solution = 22% × 0.3 = 0.066 gallon

Total amount of salt in the resulting solution = 0.035 + 0.066 = 0.101 gallon

Total volume of the resulting solution = 0.7 + 0.3 = 1.00 gallon

Concentration of the mixture of salt = (0.101/1) = 0.101 = 10.1% = 10% to the nearest percent

Hope this Helps!!!

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3 years ago
32 3/4 take away 12 1/2​
Otrada [13]

Answer:

The answer is 20 and 1/4

7 0
3 years ago
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The length of human pregnancies from conception to birth follows a distribution with mean 266 days and standard deviation 15 day
Katena32 [7]

Answer:

a) 81.5%

b) 95%

c) 75%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 266 days

Standard Deviation, σ = 15 days

We are given that the distribution of  length of human pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(between 236 and 281 days)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%

b) a) P(last between 236 and 296)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%

c) If the data is not normally distributed.

Then, according to Chebyshev's theorem, at least 1-\dfrac{1}{k^2}  data lies within k standard deviation of mean.

For k = 2

1-\dfrac{1}{(2)^2} = 75\%

Atleast 75% of data lies within two standard deviation for a non normal data.

Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.

7 0
3 years ago
Answer to the best of your abilities, pls &amp; ty !
klemol [59]

Answer:

54

Step-by-step explanation:

Por ejemplo, baile

Solamente tres estudiantes siempre lo practican.

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