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Kruka [31]
3 years ago
7

A family has two cars. The first car has a fuel efficiency of 15 miles per gallon of gas and the second has a fuel efficiency of

25 miles per gallon of gas. How many gallons were consumed by each of the two cars that week?

Mathematics
2 answers:
Elanso [62]3 years ago
6 0
How many miles did the cars go? You can’t solve the question without that.
Crank3 years ago
3 0
Hopefully it’ll help you

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If you invest $4000 at 9% interest compounded annually, in how many years will you have $20,000. Give your answer the nearest te
Masteriza [31]

Answer:

18.7 years

Step-by-step explanation:

This is a compound interest problem and the following variables have been given;

Principal = 4000; this is the amount o be invested

APR = 9%; this is the compound interest to be earned

Accumulated amount = 20,000

We are required to determine the duration in years. We apply the compound interest formula;

A=P(1+r)^{n}

20000=4000(1+\frac{9}{100})^{n}\\20000=4000(1.09)^{n}\\5=(1.09)^{n}

The next step is to introduce natural logarithms in order to determine n;

ln5=nln(1.09)\\n=\frac{ln5}{ln(1.09)}\\n= 18.675

The number of years required is thus 18.7 years

6 0
3 years ago
A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa
BlackZzzverrR [31]
<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

1/2\times1/2\times1/2\times1/2=1/16

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have 2^{4} or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = \frac{4!}{2!2!} = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = 1/2\times1/2\times1/2\times1/2=1/16

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = 1/16+1/16+1/16+1/16+1/16=5/16

6 0
3 years ago
Ms. Green has 18 pencils at her desk. Students borrow some of the pencils, and 6 pencils are left at the end of the school day.
Aleonysh [2.5K]
12 pencils were borrowed. 18- 6= 12
4 0
2 years ago
A coin and a die is rolled. What is the probability of a head and a 3?
saw5 [17]

Answer:

1/6

Step-by-step explanation:

The probability of <em>only</em> a heads on a coin is 1/2, and the probability of <em>only</em> a 3 on a die is 1/6. Multiply them together, and you get 1/6.

6 0
3 years ago
3 1/8 rounded to the closest benchmark
Karolina [17]
I have the answer but brainly is not working
3 0
2 years ago
Read 2 more answers
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