Width = w
length = w+2
f(w) =w(w+2) = w^2 + 2w.
Please, let me know whether the procedure is clear for you.
The answer is f(w)=w^2 + 2w.
You can find the segment congruent to AC by finding another segment with the same length. So first, you need to find the length of AC.
C - A = AC
0 - (-6) = AC Cancel out the double negative
0 + 6 = AC
6 = AC
Now, find another segment that also has a length of 6.
D - B = BD
2 - (-2) = BD Cancel out the double negative
2 + 2 = BD
4 = BD
4 ≠ 6
E - B = BE
4 - (-2) = BE Cancel out the double negative
4 + 2 = BE
6 = BE
6 = 6
So, the segment congruent to AC is B. BE .
I believe it’s 2% if it’s wrong sorry
