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3 years ago

Find the midpoint between the two points (1, -7) and (-1, -23).

Mathematics

1 answer:

defon3 years ago

5 0

X = (1+(-1))/2 = 0/2 = 0

y = (-7+(-23))/2 = -30/2 = -15

midpoint (0, -15)

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I really need help on this it’s really urgent. Thank you :)

Flauer [41]

Answer:

Step-by-step explanation:

$-\frac{1}{3}y - \frac{1}{3} x$

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2 years ago

Find the nth term of 6,8,10,12

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Answer:

6 8 10 12 14 16 18 20 22

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2 years ago

Suppose that the mean water hardness of lakes in Kansas is 425 mg/L and these values tend to follow a normal distribution. A lim

tino4ka555 [31]

Answer:

The mean water hardness of lakes in Kansas is 425 mg/L or greater.

Step-by-step explanation:

We are given the following data set:

346, 496, 352, 378, 315, 420, 485, 446, 479, 422, 494, 289, 436, 516, 615, 491, 360, 385, 500, 558, 381, 303, 434, 562, 496

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{10959}{25} =438.36$

Sum of squares of differences = 175413.76

$S.D = \sqrt{\dfrac{175413.76}{24}} = 85.49$

Population mean, μ = 425 mg/L

Sample mean, $\bar{x}$ = 438.36

Sample size, n = 25

Alpha, α = 0.05

Sample standard deviation, s = 85.49

First, we design the null and the alternate hypothesis

$H_{0}: \mu \geq 425\text{ mg per Litre}\\H_A: \mu < 425\text{ mg per Litre}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{438.36 - 425}{\frac{85.49}{\sqrt{25}} } = 0.7813$

Now, $t_{critical} \text{ at 0.05 level of significance, 24 degree of freedom } = -1.7108$

Since,

The calculated t-statistic is greater than the critical value, we fail to reject the null hypothesis and accept it.

Thus, the mean water hardness of lakes in Kansas is 425 mg/L or greater.

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3 years ago

Given that the chord ef is a diameter of circle d which of the following names major arc

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3 years ago

The volume of a cone is 1/3 that of a cylinder when the radius and height are the same (v= 1/3(pi)(r)^2(h). What is the volume o

Ira Lisetskai [31]

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Surface Areas and Volumes.

Since, Volume of cone = 1/3 π r^2 h,

here, r = 10 Inches and h= 12 inches, also π =3.14

so, VOC = 1/3 π (10)^2 × (20)

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=> so the volume of the cone is 2093.33 cubic inches.

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2 years ago