1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Masteriza [31]
4 years ago
12

Kobe, A'mari and DJ are raising money for their football team to take a trip to San Diego. Kobe collected $18.50 more than A'mar

i, and DJ collected $12.25 less than Kobe. Altogether, the three boys collected $95.70. How much did Kobe collect?
Mathematics
2 answers:
ira [324]4 years ago
6 0

Answer:

So Kobe collected $42.15

Step-by-step explanation:

Kobe, A'mari and DJ are raising money for the football team to take a trip to San Diego.

Let x = amount which Kobe collected

Let y = amount which Amari collected

Let z= amount which Dj collected.

Kobe collected $18.50 more than A‘Mari. This means

x= y + 18.5 - - - - - - 1

DJ collected $12.25 less than Kobe

z = x-12.25 - - -- - - - - 2

Total sum collected by the 3 boys

= $95.70 This means

x + y+ z= 95.70 - -- - -- - -3

Put x = y + 18.5 in equation 3 and also

x= z+12.25 in equation 3

y + 18.5 + y+ z= 95.70

2y +z = 95.70-18.5 = 77.2

2y +z = 77.2 - - - - - -4

z + 12.25 + y+ z= 95.70

y +2z = 83.45 - - - - - -- - 5

Multiply equation 4 by 1 and equation 5 by 2

2y +z = 77.2

2y + 4z = 166.9

-3z = -89.7

z = 89.7/3= 29.9

Put z =29.9 in 2y+z = 77.2

2y +29.9= 77.2

2y = 77.2-29.9= 47.3

y = 47.3/2 = 23.65

Put y=23.65 and z = 29.9 in equation 3

x + 23.65+ 29.9= 95.70

x = 95.70-53.55

=$42.15

So Kobe collected $42.15

WITCHER [35]4 years ago
6 0

Answer:

42.15

Step-by-step explanation: Simple math.

You might be interested in
Place the following steps in order to complete the square and solve the quadratic equation, x^2 - 6x + 7 = 0.
kow [346]

Answer:

option f

option a

option d

option c

option e

option b

Step-by-step explanation:

we have x^2 - 6x + 7 = 0

f) x^2 - 6x   = -7    

a) x^2 - 6x + 9 = -7+9

d) (x-3)^2=2

c)\sqrt{(x-3)^{2}} = +-\sqrt{2}

e) x-3=+-\sqrt{2}

b) x=3+-\sqrt{2}

4 0
3 years ago
Read 2 more answers
VERY URGENT
cricket20 [7]

Answer:

Larger number: 22

The smaller number: 14

HOPE THIS HELPS

8 0
3 years ago
Bfmnbv help will give brainly
Inga [223]

Answer:

tell your friend yall in zooooom

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Determine whether the equation has no solution, one solution, or infinitely many solutions. 7(12 – 2 x ) = 4(3 – 3 x )
Alex777 [14]

Answer: The equation has one solution

Step-by-step explanation: First , open the brackets

7( 12 - 2x ) = 4 (3 - 3x )

84 - 14x = 12 - 12x

collect the like terms

84 - 12 = - 12x + 14x

72 = 2x

Therefore divide through by 2

x = 72/2

x = 36

Therefore, the equation has only one solution

3 0
3 years ago
I have 2 thousands,12 tens,5 hundred and 9 one
12345 [234]

Answer:

2 120 500 9. so 2,629 would be the answer

7 0
3 years ago
Other questions:
  • Divide x to the 3 fifths power divided by x to the 1 fourth power.
    5·2 answers
  • Mr.jones is planning to plant grass and place a fence in a small area for his dog the rectangular dimensions are 12 x15 feet the
    6·2 answers
  • Please help I’m stuck.
    10·1 answer
  • Mary has rehearsed her ballet solo for five and a half hours. A week from now, she wants to have rehearsed at least a total of n
    11·1 answer
  • PLS HELP ASAP!!<br><br> Please can someone write this out for me ill crown heart u and all!!&lt;3
    5·1 answer
  • A circle has a circumference of 12 inches. What is the approximate area of the circle?
    10·1 answer
  • What is the probability of choosing a king from a deck of cards? Type your answer as a fraction.
    15·2 answers
  • BRAINLIEST!!! See pic BELOW!!!
    11·2 answers
  • X/6&gt;-8 . Can you exsplain to me how you do this answer for my math class
    5·2 answers
  • How to graph f(x)=(x-2)^2+3
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!