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Gelneren [198K]
3 years ago
7

The equation 2x + 4k − 9 = kx − k + 1 is really a family of equations, because for each value of k, we get a different equation

with the unknown x. the letter k is called a parameter for this family. what value should we pick for k to make the given value of x a solution of the resulting equation? (if all real numbers are solutions, enter reals.)
Mathematics
1 answer:
Olegator [25]3 years ago
3 0
You haven't shared "the given value of x," or, if you have, you haven't drawn attention to it.

Just suppose we were to choose x = 4 as a possible solution and then try to find a value of the parameter k that would make x = 4 an actual solution.

2(4) + 4k - 9 = (4)(4) - (4) + 1

Then 8 + 4k - 9 = 16 - 4 + 1, or       4k - 1 = 13.  Then 4k = 14, and k = 14/4, or (after reduction)  k = 7/2   

If the parameter k equals 7/2, then x = 4 is a solution to the given equation.

To check this out further, start with the proposed solution x = 5 and find k.
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What is the answer to this equation |x−1|+5=2
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Answer:

No solutions

Step-by-step explanation:

Isolate the absolute value:

|x−1| + 5 = 2

Subtract 5 from both sides:

|x-1| = -3

Since an absolute value can never be equal to a negative number, there are no solutions.

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3 years ago
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What is the slope of the line that contains the points (2, -6) and (-3, 1)?
jolli1 [7]
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Convert to an improper fraction. Type in your answer with the negative in the numerator. -8 3/4 =
Sergeu [11.5K]

Answer:

-32/4

Step-by-step explanation:

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3 years ago
What is the length (magnitude) of vector (-4,2)
VladimirAG [237]

Answer:

2√5

Step-by-step explanation:

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3 years ago
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Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.
Setler79 [48]

Answer:

Therefore values of a and b are

a=3\ and\ b = 2

Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

(x-a)^{2}=b

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9

Adding half coefficient of X square on both the side we get

x^{2}-6x+9=-7+9=2 ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}

Substituting in equation 1 we get

(x-3)^{2}=2

Which is in the form of

(x-a)^{2}=b

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

4 0
3 years ago
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