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Gelneren [198K]
4 years ago
7

The equation 2x + 4k − 9 = kx − k + 1 is really a family of equations, because for each value of k, we get a different equation

with the unknown x. the letter k is called a parameter for this family. what value should we pick for k to make the given value of x a solution of the resulting equation? (if all real numbers are solutions, enter reals.)
Mathematics
1 answer:
Olegator [25]4 years ago
3 0
You haven't shared "the given value of x," or, if you have, you haven't drawn attention to it.

Just suppose we were to choose x = 4 as a possible solution and then try to find a value of the parameter k that would make x = 4 an actual solution.

2(4) + 4k - 9 = (4)(4) - (4) + 1

Then 8 + 4k - 9 = 16 - 4 + 1, or       4k - 1 = 13.  Then 4k = 14, and k = 14/4, or (after reduction)  k = 7/2   

If the parameter k equals 7/2, then x = 4 is a solution to the given equation.

To check this out further, start with the proposed solution x = 5 and find k.
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aalyn [17]

Answer:

Correct option: 2 -> sqrt(37)

Step-by-step explanation:

To solve this problem, we just need to use the law of cosines. This law is used to find the third side of a triangle, when we have the two other sides and the angle between them.

The equation of the law of cosines is:

c^2 = a^2 + b^2 - 2 * a * b * cos(C)

So, we have that:

c^2 = 7^2 + 3^2 - 2 * 7 * 3 * (1/2)

c^2 = 49 + 9 - 21

c^2 = 37

c = sqrt(37)

Correct option: 2

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Step-by-step explanation:

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3 years ago
Please solve (-3×+15)+(-3×+2)
koban [17]
(-3x + 15) + (-3x + 2)
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Answers/Step-by-step explanation:

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105

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