One way is to make it into slope intercept form which is
y=mx+b
m=slope
b=y intercept or where the line will go though the y axis
treat the equal to or greater than sign as equals for now
5x-y=5
subtract y from both sides
5x=5+y
subtract 5
5x-5=y
put the sign back in
5x-5 ≥ y
reverse
y ≤ 5x-5
one way is to subsitute values and get values out so
if x=1 then
y≤5(1)-5
y≤0
(x,y)
(1,0)
(2,5)
(3,10)
(4,15)
(0,-5)
plot the points
then the ≤ sign
since ther is an underline, that means that the points are included so draw a solid line through the points
then figure out which side to shade on
the easy way is, is the point (0,0) a solution?
subsitute
0 ≤ 5(0)-5
0 ≤ -5
false so we shade the section that does not include the point (0,0) in it
the graph would look like this attachment
Answer:
0.25
Step-by-step explanation:
Given that:
Number of options per question = 4
Number of correct answer per question = 1
Number of incorrect answers per question = 3
By random guess:
Probability of picking a correct answer :
Number of correct answers / number of options
= 1 / 4 = 0.25
Probability of picking an incorrect answer :
Number of incorrect answers / number of options
= 3/4
Hence,
X :______ 4 _____ - 1
P(X) : ___ 0.25 __ 0.75
Σ(X*P(x))
(4 * 0.25) + (-1 * 0.75)
1 + (-0.75)
1 - 0.75
= 0.25
Answer:
2p+27
Step-by-step explanation:
6p+15-4p+15-3
2p+27
Answer:
The distance of Musah's final point from the center in the west direction is 60.355 steps
The distance of Musah's final point from the center in the north direction is 85.355 steps
Step-by-step explanation:
Given that :
Musah stands at the center of a rectangular field.
He takes 50 steps north, then 25 steps West and finally 50 on a bearing of 315°.
The sketch for Musah's movement is seen in the attached file below.
How far west is Musah's final point from the centre?
In order to determine how far west is Musah's,
Let d be the distance of how far west;
Then d = BC + CD cos θ
In the North West direction,
cos θ = cos 45°
d = 25 + 50( cos 45°)
d = 25 + 50( )
d = 25 + 50( 0.7071)
d =25 + 35.355
d = 60.355 steps
How far north is Musah's final point from the center?
Let d₁ be the distance of how far North;
Then d₁ = AB + CD sin θ
d₁ = 50 + 50 sin 45°
d₁ = 50 + 50( )
d₁ = 50 + 50( 0.7071)
d₁ = 50 + 35.355
d₁ = 85.355 steps