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Brrunno [24]
2 years ago
8

Help 30 pts plus brainliest

Mathematics
1 answer:
avanturin [10]2 years ago
5 0

Answer:

c. 113

Step-by-step explanation:

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Math question screen shot down below
ser-zykov [4K]

Answer:

11

Step-by-step explanation:

11,16,12,7,23,9,5,5

arrange to least to greatest

5,5,7,9,11 ,12,16,23

2 middle numbers

11+12= 23

23÷2= 11.5

Median is 11

3 0
3 years ago
Read 2 more answers
HELP PLEaseeeeeeeeeeeee thank youi
avanturin [10]

Answer:

d=4.5t

Step-by-step explanation:

in two hours, Francine went 9 miles

9/2=4.5

the distance equals 4.5 times each cycling time.

d=4.5t

7 0
2 years ago
Read 2 more answers
Help me please Help me please Help me please Help me please Help me please Help me please Help me please Help me please Help me
levacccp [35]

Answer:

5 units

Step-by-step explanation:

You can use the distance formula or pythagorean theorem to solve this.

Original point A: (0,0)

New point B: (3, 4)

Distance formula: \sqrt{(x_{2}-x_{1})^{2}   +(y_{2}-y_{1})^{2} }

Plug the points in:

\sqrt{(3-0)^{2} +(4-0)^{2} } = 5

5 units

5 0
3 years ago
Solve for x please, explantion is not nesscary but it would help me
Ber [7]

Answer:

x = 100 degrees

Step-by-step explanation:

There are 360 degrees total in this figure. Since 160 is already shown, we can subtract it from 360 to solve for x. 360 - 160 = 200. So, 200 degrees is split among the remaining values, which are 2 x's. Since each x has the same value, we can divide 200 evenly among the two of them. 200/2 = 100. So, x = 100.

P.S.: Sorry if this is long-winded, I haven't taken geometry in a while. I hope I explained it well enough for you and other Brainly users.

7 0
3 years ago
Linda goes water-skiing one sunny afternoon. After skiing for 15 min, she signals to the driver of the boat to take her back to
trasher [3.6K]
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2


abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.


d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
4 0
3 years ago
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