The volume of aggregate that she needs to build the patio is 13.18 ft^3
<h3>How many cubic feet of aggregate would she need to build the walkway?</h3>
We know that the backyard is 14ft long, 6 feet wide and 4 inches deep.
Rememeber that:
1ft = 12 in
Then:
4 in = (4/12) ft = (1/3) ft
Then the volume of the backyard is:
V = (14ft)*(6ft)*(1/3 ft) = 28ft^3
Now we know that we have a mix of 4 parts aggregate to 4.5 parts loose cement that need to fill these 28 cubic feet.
Note that:
4 + 4.5 = 8.5
How many times we have 8.5 in 28?
28/8.5 = 3.294
Now for each of these we have 4 parts of aggregate, then the volume of aggregate that we need is:
4*3.294 ft^3 = 13.18 ft^3
The volume of aggregate that she needs to build the patio is 13.18 ft^3
If you want to learn more about volumes:
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B is the only answer that would make sense.
Did you notice the little box with corners marked in the angle down at the bottom ?
That angle is a right angle, and <em>this triangle is a right triangle</em> !
This piece of information is a big help. It breaks the problem wide open.
You know that in order to find the longest side of a right triangle . . .
-- Square the length of one short side.
-- Square the length of the other short side.
-- Add the two squares together.
-- Take the square root of the sum.
One short side=48. Its square = 2,304.
The other short side=48. Its square = 2,304.
Add the two squares: 2,304 + 2,304 = 4,608
The square root of the sum = √4,608 = <em><u>67.88</u></em> (rounded)
Answer:
Hi there!
Your answers are:
1) x> 5
Some numbers that would fit this equation are 6, 7, 8, etc!
2) x<= 30
Some numbers that would fit this are 30, 29, 28, etc!
3) x>= 17
Some numbers that would fit this equation are 17, 18, 19, etc!
4) x>= 90
Some numbers that would fit this are 90, 91, 92, etc!
Hope this helps!
