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3 years ago

What is the overlap of data set 1 and data set 2 A. High B.moderate C.low D.none

Mathematics

1 answer:

finlep [7]3 years ago

7 0

It's definitely a low data overlap. It's not medium because there's not a solid amount of matching data, and its not 'none' because there is matching data.
so it’s C.

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The diagonals of a kite have lengths of x inches and 18x inches. The area of the kite is given by A=9x^2. Identify the equation(

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Step-by-step explanation:

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3 years ago

The composition ry-axisT(0, 2) is used to transform a triangle having a vertex at (0, 1). Describe how to find the coordinates o

Tpy6a [65]

Answer:

Sample Response: Perform the transformations from right to left. First, rotate the triangle 90 degrees. Negate the y-coordinate and then switch the coordinates to get (–1, 0). Next, perform the translation up by adding 0 to the x-coordinate and 2 to the y-coordinate to get (–1, 2). Finally, reflect this point over the y-axis by negating the x-coordinate to get (1, 2).

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3 years ago

What’s the answer to this?

jeka57 [31]

Answer:

y=3/2x+0

Step-by-step explanation:

The formula for slope intercept form formula is y=mx+b where m is the slope and b is the y intercept and since the slope is rise over run ( or rise/run just put it into fraction form) we count from the y intercept up until we can see the line reach a point where it touches a actual cross point ( in this case from the y intercept we see it goes up three) Then we count over how many to that cross point ( the full point, not just a random place on the chart) (in this case 2) and that creates 3/2. Now for the y intercept. Where does the line intercept the vertical line? That's your y intercept. In this case it's 0. Now you can see where we count up from three ( for the slope) and over two. Right onto that point. Hope this makes sense! If not look up Khan academy for some extra tutoring that is free.

Hope this helps! If so please mark brainliest and rate/heart if it did.

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3 years ago

To meke a batch of sugar cookies , you need 0.75 cup of sugar and 1/3 cup of butter , among other ingredients. How much more sug

Leokris [45]

A) 5/12 cup more

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3 years ago

Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time t > 0 is $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

$\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t$

where, $\text{R}_i_n$ = concentration of salt in the inflow $\times$ input rate of brine solution

and $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

So, $\text{R}_i_n$ = 4 lb/gal $\times$ 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

= 3 gal/min - 2 gal/min

= 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

= $\frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min}$ = $\frac{2A(t)}{500+t} \text{ lb/min }$

Now, the differential equation for the amount of salt A(t) in the tank at a time t > 0 is given by;

= $\frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }$

or $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

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3 years ago