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kirill115 [55]
3 years ago
7

David and Amarita had an equal number of marbles.After amirita gave 50marbles to David, he had 5times as many marbles as her. Fi

nd the total number of marbles they had
Mathematics
1 answer:
faltersainse [42]3 years ago
8 0

Answer:

250 marbles

Step-by-step explanation:

50x5=250 marbles

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bezimeni [28]

Answer:

B. 6.2

Step-by-step explanation:

The calculation is done by hand and verified by a TI-84 calculator.

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2 years ago
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A ladder is placed 7 feet from the base of a building and reaches a point on the building that is 24 feet above the ground.Find
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2 years ago
I hate this pain i got through i just cant anymore...<br><br> y+50=700
DiKsa [7]

Answer:

y=650

Step-by-step explanation:

Just subtract 50 from each side

And Yes, please

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3 years ago
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What is the value of f?
laiz [17]

Answer:

f(1/2) = -2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 8x - 6

f(1/2) is x = 1/2

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    f(1/2) = 8(1/2) - 6
  2. Multiply:                               f(1/2) = 4 - 6
  3. Subtract:                              f(1/2) = -2
5 0
3 years ago
In Triangle XYZ, measure of angle X = 49° , XY = 18°, and
marissa [1.9K]

Answer:

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X (1)

If we know that X = 49^{\circ}, XY = 18 and YZ = 14, then we have the following second order polynomial:

14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}

XZ^{2}-23.618\cdot XZ +128 = 0 (2)

By the Quadratic Formula we have the following result:

XZ \approx 15.193\,\lor\,XZ \approx 8.424

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y

\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}

Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)

1) XZ \approx 15.193

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 54.987^{\circ}

2) XZ \approx 8.424

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 27.008^{\circ}

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

6 0
2 years ago
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