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Rudiy27
3 years ago
7

How do I solve 3(-2+3)>12

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0
First do the -2+3 since its in the Parentheses. So now your left with 1 times 3 >12. 
Then you do the multiplication so now you're left with 3>12 which isn't true.

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How many times does the quadratic function below intersect the x-axis?<br> y = 2x2 +7x+6
sattari [20]

Answer:

once

Step-by-step explanation:

since the equation is liner, with x simply to the first power, it will only cross the x axis once. x^2 would cross the x axis twice, x^3 would cross it three times, and so on

6 0
3 years ago
Rewrite the fraction as a decimal 13/11 = Round to the nearest hundredth.​
Allisa [31]

Answer:

1.18

Step-by-step explanation:

4 0
3 years ago
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strojnjashka [21]

Answer:

x = 0

Step-by-step explanation:

{2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {9}^{x } } \\  \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {( {3}^{2}) }^{x } } \\  \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {({3)}^{2x}}}\\  \\ {2}^{x} -  \cancel{{3}^{x}} = \sqrt{ {6}^{x} } - \cancel{ {3}^{x} } \\  \\ {2}^{x} = \sqrt{ {6}^{x} } \\ squaring \: both \: sides \\  \\  {( {2}^{x} )}^{2}  =  {(\sqrt{ {6}^{x} })}^{2}  \\  \\  {2}^{2x}  =  {6}^{x}  \\  \\   {2}^{2x}  =  {(2 \times 3)}^{x}  \\  \\   {2}^{2x}  =  {2 ^{x}  \times 3}^{x}  \\  \\  \frac{ {2}^{2x}  }{ {2}^{x}  } =  3^{x}  \\  \\   {2}^{2x - x}  =  {3}^{x}  \\  \\  {2}^{x}  =  {3}^{x}  \\  \\   \frac{ {2}^{x} }{ {3}^{x} }  = 1 \\  \\  \bigg(  \frac{2}{3} \bigg)^{x}  = 1 \\  \\  \implies \: x = 0 \\  \\  \because \: for \: x = 0 \\  \\ \bigg(  \frac{2}{3} \bigg)^{0}  = 1

5 0
3 years ago
What’s the answer to 5 1/2 x ? = 10
myrzilka [38]
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3 0
3 years ago
Is the relationship a function? (Show work if possible)
MakcuM [25]

Answer: No! This is not a function!

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
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