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3 years ago

If f(x)=8-3|x+2|, find f(-6)

2 answers:

5 0

To find f(-6), simply plug -6 in for x in the equation.
$f(x)=8-3|x+2|$
$f(-6)=8-3|-6+2|$
$f(-6)=8-3|-4|$
$f(-6)=8-3*4$
$f(-6)=-4$

Hope that helps!

alex41 [277]3 years ago

3 0

-6=-4
no solutions
hope this helps

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Step-by-step explanation:

we know that

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Part 1) we have

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we know that

In a quotient the denominator cannot be equal to zero

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therefore

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Part 2) we have

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therefore

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Part 3) we have

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Part 4) we have

$f(x)=\frac{4}{x^2+8x+16}$

we know that

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Equate the denominator to zero

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Remember that

$x^2+8x+16=(x+4)^2$

( $x+4)^2=0$

The solution is x=-4

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