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pshichka [43]
3 years ago
7

PLS HELP!!

Mathematics
1 answer:
Jet001 [13]3 years ago
8 0

Answer:

Part 1) The radius of the circle is 17\ units

Part 2) The points (15,14) and (-15,-16) lies on this circle

Step-by-step explanation:

Part 1

we know that

The distance between the center of the circle at point (-7,-1) and the point (8,7) is equal to the radius of the circle

so

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

r=\sqrt{(7+1)^{2}+(8+7)^{2}}

r=\sqrt{(8)^{2}+(15)^{2}}

r=\sqrt{289}}

r=17\ units

Part 2

we know that

If the point (-15,y) lies on the circle, then the ordered pair must be satisfy the equation of the circle

The equation of the circle is equal to

(x+7)^{2}+(y+1)^{2}=17^{2} -----> equation of the circle in center radius form

substitute the value of x=-15 in the equation and solve for y

(-15+7)^{2}+(y+1)^{2}=289

64+(y+1)^{2}=289

(y+1)^{2}=289-64

(y+1)^{2}=225

y+1=(+/-)15

y=-1(+/-)15

so

y=14

y=-16

therefore

The points (15,14) and (-15,-16) lies on this circle

see the attached figure to better understand the problem

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