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scZoUnD [109]
3 years ago
8

There are 20 squid and 36 eels in a fish tank. What is the ratio of squids to eels? What is the rate of squids to eels? What abo

ut the simplified ratio and unit rate?
Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
7 0

Answer:

Ratio: 20:36

Rate: 20 squids per 36 eels

Simplified ratio:

=  \frac{20}{36 }  = \frac{10}{18}  =  \frac{5}{9}

Unit ratio:

20/36 squids per eel (dividing by 36)

Please mark Brainliest if this helps!

Gre4nikov [31]3 years ago
4 0

Answer:

Step-by-step explanation:

Number of squid in the tank = 20

Number of eels in the tank = 36

Rate of squids to eels will be obtained by creating a fraction of number of squids over number of eels

Rate of squid to eels = \frac{20}{36}

also ratio of squid to eels will be written as 20:36

Simplified ratio = \frac{20}{36} = \frac{5}{9} = 5:9

Unit rate will be defined as number of squid per eels

Unit rate = \frac{20}{36} = 0.55

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2 years ago
the cost of a personal pizza is $4. a drink cost $1. Anna wrote the equation y=4x + 1 to represent the relationship between tota
valentinak56 [21]
The correct answer should be y=4x + 1d where x equals the number of personal pizzas, and d equals the number of drinks.

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3 0
3 years ago
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Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.
statuscvo [17]

Answer:

A, D, E are true

Step-by-step explanation:

You have to complete the square to prove A.  Do this by first setting the function equal to 0, then moving the 5 to the other side.

x^2-8x=-5

Now we can complete the square.  Take half the linear term, square it, and add it to both sides.  Our linear term is 8 (from the -8x).  Half of 8 is 4, and 4 squared is 16.  So we add 16 to both sides.

(x^2-8x+16)=-5+16

We will do the addition on the right, no big deal.  On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex.  We will rewrite with that perfect square on the left and the addition done on the right,

(x-4)^2=11

Now we will move the 11 back over, which gives us the k coordinate of the vertex.

(x-4)^2-11=y

From this you can see that A is correct.

Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.

The axis of symmetry is also found in the h value.  This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation.  In the case of this type of parabola, that "x = " will always be equal to the h value.  So the axis of symmetry is

x = 4, which is why C is NOT correct, either.

We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x.  When we do that, and then solve for y, we find that when x = 0, y = 5.  So the y-intercept is (0, 5).

From this you can see that D is also correct.

To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x.  I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice.  Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0).  That's why you need the quadratic formula to find these values.

7 0
3 years ago
I’m not sure what to do, this was what I got. Someone please help and solve problem #14 in the picture. Thanks!
mars1129 [50]

Answer:

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  • AM = BM = 16

Step-by-step explanation:

Your problem setup is correct. The triangle is isosceles, so the marked segments are the same length.

  3x - 8 = 2x

You can solve this by subtracting 2x (from both sides) ...

  x - 8 = 0

Then adding 8 (to both sides):

  x = 8

MB = MA = 2x = 16.

4 0
3 years ago
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Dahasolnce [82]
- cos ( 1/2 x + 1/5 π ) = 0 ( and because if cos α = 0, α= π/2 + k π, k ∈ Z )
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1/2 x = π/2 - π/5 + k π  / * 2
x = π - 2π/5 + 2 k π
x = 3/5 π + 2 k π = 0.6 π + 2 k π
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3 0
3 years ago
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