Answer:
Solution given:
South distance :base[b]=80milea
East distance :perpendicular [p]=35miles
Now
<S=?
we have


=24°
24° bearing should be taken from south airport to East airport.
Answer:
maximum is 16,853 cell phones
≤ 18.853
Step-by-step explanation:
1,176,912.42. per quarter budget
247,638.00 per quarter fixed cost
We subtract then divide the amount cost of phones and ensure its less or rounded down.
1,176,912.42 -247,638 = 929274.42
929274.42 / 55.14 = 16853
16,852 < m ≤ 16,853
Answer:
multiplication, so d, 2 x 3
Step-by-step explanation:
remember... PEMDAS!!
2.5 weighs more. It’s a greater number than 2.48