*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*
(21)
Area of a Regular Hexagon: 
square units
(22)
Similar to (21)
Area = 
square units
(23)
For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:
Hence, area of the hexagon will be: 
square units
(24)
Given is the inradius of an equilateral triangle.
Substituting the value of inradius and calculating the length of the side of the equilateral triangle:
Side = 16 units
Area of equilateral triangle = 
square units
its -325
:3
hope this helped gooooood luck ;3
Answer:
P = - 15
Step-by-step explanation:
P+7-5 = -10 - 3
P +2 = - 13
(If taking from one side,you must do to the other to get P alone.)
P+2 = - 13
-2 = - 2
The positive 2, minus the negative 2 cancels each other out, now we must subtract 2 from our other side. - 13 - 2 = - 15
P = -15
Answer:
y = -5/3x + 3
Step-by-step explanation:
First lets turn the equation from standard form to slope intercept form.
3x - 5y = 1
~Subtract 3x to both sides
-5y = 1 - 3x
~Divide -5 to everything
y = -1/5 + 3/5x
~Reorder
y = 3/5x - 1/5
Now that we have the equation in slope intercept form, we can find the new equation. A perpendicular line will have the opposite reciprocal of the original slope.
3/5x -> -5/3x
Now that we have the slope, we can use the given point to find the y-intercept.
y = -5/3x + b
8 = -5/3(-3) + b
8 = 5 + b
3 = b
Put all the information we solved for into a final equation.
y = -5/3x + 3
Best of Luck!
Please refer to the attachment for the answer and explanation. Hope it helps!!
