Yes seth your answers are all corret i seen them i did that paper too
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We have 22 tickets sold, and 20 seats. This means that at least 2 passengers must not show up (otherwise, at least 21 passengers will be present, and there wouldn't be space for them).
Considering each passenger as independent, you can think of this experiment. Suppose you toss a coin for each passenger. If the coin lands on heads, the passenger shows up. If it lands on tails, the passenger doesn't show up.
But the coin is unfair: it has a 0.91 probability of landing on heads, and thus 0.09 probability of landing on tails.
This implies that the probability of having exactly
tails is

We already concluded that at least two passengers must not show up. So, if our coins lands on tails less than twice, we've lost. So, the losing probability is

Finally, remember the rule to negate events:

So, if we lose with probability 0.39, we win with probability

40+1
50-9
4(10)+1
410/10
There are a lot of answers
The expression that is equivalent to 3t + 3t is 6t