Answer: 1.58 hours
<u>Step-by-step explanation:</u>
Step-by-step explanation:
Im not sure if its supposed y = -2x + 1 or y = 2x + 1 but I'll solve the problem for both.
First for y = -2x + 1
Since the line has to be parallel to y = -2x + 1
the slopes would be the same.
so, so far the equation would be
y = -2x + b
now we substitute (5,2) into the equation
2 = -2(5) + b
2 = -10 + b (Add 10 to both sides of the equation)
+10 +10
12 = b
Now that we solved for b
The equation would be
y = -2x + 12
^^ This equation is parallel to y = -2x + 1
Now to solve for an equation parallel to y = 2x + 1
Both equations would have the same slope
So far we would have
y = 2x + b
Now we solve for be by substituting the point (5,2)
2 = 2(5) + b
2 = 10 + b (subtract 10 from both sides)
-10 -10
-8 = b
After solving for b
The equation is
y = 2x - 8
This equation is parallel to y = 2x + 1
There is one solution:
use elimination method
5x - 7y = 12
5y - 2x = -7 ---> change equation around
5x - 7y = 12
-2x + 5y = -7
2 x ( 5x - 7y) = 2 x (12) multiply both sides by 2
5 x (-2x +5y) = 5 x (-7)
this give you
10x - 14y =24
-10x+25y = -35 add down
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11y = - 11 x is eliminated to find y value
y = -1 input to one of the original equations
5(-1) - 2x = -7
-5 - 2x = -7
+5 +5 add 5 to both sides
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-2x = -2
x = 1
your coordinates for when they intersect is at (1, -1)
one solution
Eq. of given line is x = -2 》x + 2 = 0
