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kolbaska11 [484]
3 years ago
11

Select all pairs of numbers that have LCM of 18?

Mathematics
1 answer:
spayn [35]3 years ago
8 0
Only C and D....................
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PLEASE HELP!!!!
Kipish [7]

The system of inequalities for the specific graph is

1. (one on top) y ≤ 1/2x + 6

2. (one on bottom) y > 1/2x -2

Hope this helped! :D

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20-%201%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7Bx%20%2B%202%7D%7B3%7D%20" id="TexForm
Lyrx [107]

Hey there!!

Given equation :

( x - 1 ) / 4 = ( x + 2 ) / 3

First step we will need to take is to cross-multiply. In cross-multiplication, we will have t multiply the denominator with the numerator on both the sides. In this case, we will have to multiply 4 with x + 2 and 3 with x - 1.

... 4 ( x + 2 ) = 3 ( x - 1 )

... 4x + 8 = 3x - 3

Subtract 3x on both sides.

... x + 8 = -3

Subtract 8 on both sides

... x = - 11

Hope my answer helps!

6 0
3 years ago
1
aleksklad [387]

Answer:

.4 is the answer

Step-by-step explanation:

2÷5= .4

7 0
2 years ago
Read 2 more answers
The cost for x number of students to attend an after school sporting event can be represented bu the functon C(x). If C(124) = 5
lara [203]
Alright! Given that C(x) is Cost(Students) = 558, we can eliminate:

2. 558 students paid to attend the event.
5. The event generated $124 from student revenue.

Now, in order to find the cost per student we simply divide 124 on both sides:

\frac{C(124)}{124} =  \frac{558}{124}

124 cancels on the left and 558/124 is 4.5 or $4.50. 

Since we just determined the cost of one student, we can eliminate 3.

To check if 124 students paid, we simply add the cost to the equation and check:

4.5(124) = 558

558 = 558 √

It checks out, so we determined that both 1 and 4 are correct.
7 0
3 years ago
A rectangle has long sides measuring 4 cm and short sides measuring 3 cm. What is the area of this rectangle?
bearhunter [10]
Area of this rectangle
4×3=12cm^2

formula
long side×short side=area of this rectangle
8 0
2 years ago
Read 2 more answers
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