Answer:
<u>dollars per hour rate = $10</u>
<u>hours per dollar = 6 minutes 15 seconds</u>
Step-by-step explanation:
Take note that one is singular (dollar) without an 's', and the other is plural (dollars). Thus, since her dollars per hour rate tells us how much she will earn for each hour of work, we would expect her hours per dollar rate to tell us how much she has to work in minutes to earn a single dollar ($1).
If we divide 
= $0.16 which indicates how much she earns for every minute she works at the theater. Further dividing this value into 1 minute we find the hour per dollar rate 1/0.16 = 6.25. minutes.
Answer:
huh
Step-by-step explanation:
did you add anything?
Solving for x
x=3/8m-5/4,m
Solving for m
m=10/3+8/3x,x
Given that t<span>he
desired percentage of sio2 in a certain type of aluminous cement is
5.5. to test whether the true average percentage is 5.5 for a particular
production facility, 16 independently obtained samples are analyzed.
suppose that the percentage of sio2 in a sample is normally distributed
with σ = 0.32 and that
.
</span>
<span>To investigate whether this indicate conclusively that the true average
percentage differs from 5.5.
Part A:
From the question, it is claimed that </span><span>t<span>he
desired average percentage of sio2 in a certain type of aluminous cement is
5.5</span></span> and we want to test whether the information from the random sample <span>indicate conclusively that the true average
percentage differs from 5.5.
Therefore, the null hypothesis and the alternative hypothesis is given by:
Part B:
The test statistics is given by:
Part C:
The p-value is given by
Part D:
Because the p-value is less than the significant level α, we reject the null hypothesis and conclude that "</span><span>There is sufficient evidence
to conclude that the true average percentage differs from the
desired percentage."
Part E:
</span>If the true average percentage is μ = 5.6 and a level α = 0.01 test based on n =
16 is used, what is the probability of detecting this departure
from H0? (Round your answer to four decimal
places.)
The probability of detecting the departure
from
is given by
Part F:
What value of n is required to satisfy
α = 0.01 and β(5.6) = 0.01? (Round your answer up
to the next whole number.)
The value of n is required to satisfy
α = 0.01 and β(5.6) = 0.01 is given by
![n=\left[ \frac{\sigma(z_{0.005}+z_{0.01})}{\mu_0-\mu} \right]^2 \\ \\ = \left[\frac{0.32(-2.576-2.326)}{5.5-5.6} \right]^2 \\ \\ =\left[\frac{0.32(-4.902)}{-0.1} \right]^2=\left[\frac{-1.56864}{-0.1} \right]^2 \\ \\ =(15.6864)^2=247](https://tex.z-dn.net/?f=n%3D%5Cleft%5B%20%5Cfrac%7B%5Csigma%28z_%7B0.005%7D%2Bz_%7B0.01%7D%29%7D%7B%5Cmu_0-%5Cmu%7D%20%5Cright%5D%5E2%20%5C%5C%20%20%5C%5C%20%3D%20%5Cleft%5B%5Cfrac%7B0.32%28-2.576-2.326%29%7D%7B5.5-5.6%7D%20%5Cright%5D%5E2%20%5C%5C%20%20%5C%5C%20%3D%5Cleft%5B%5Cfrac%7B0.32%28-4.902%29%7D%7B-0.1%7D%20%5Cright%5D%5E2%3D%5Cleft%5B%5Cfrac%7B-1.56864%7D%7B-0.1%7D%20%5Cright%5D%5E2%20%5C%5C%20%20%5C%5C%20%3D%2815.6864%29%5E2%3D247)
