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Slav-nsk [51]
3 years ago
6

How to do assignment 5 on edhesive please help

Computers and Technology
1 answer:
Shalnov [3]3 years ago
8 0

Answer:

//To enter a string, and enter a pivot string, and then print in required sequence, the string from pivot string to last as first string, and printed before the left portion of string.

import java.util.Scanner;

public class Main {

 public static void main(String args[]) {

   Scanner s1 = new Scanner(System.in);

   System.out.println("Enter Main String:");

   String f1 = s1.nextLine();

   System.out.println("Enter pivot(string):");

   String piv = s1.nextLine();

   int start1 = f1.indexOf(piv);

   int end1 = piv.length()+start1;

   if (start1 == -1){

     System.out.println("Error: Sub string(Pivot) cannot be found.");

     return;

   }

   String first1 = f1.substring(0,start1-1);

   String second1 = f1.substring(end1);

   if (f1.charAt(start1-1)==' '){

     System.out.println(second1 + " " + piv + " " + first1);

     return;

   }

   System.out.println(second1 + piv + first1);

   

 }

}

Explanation:

Please check the answer section

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Answer:

C: The protocols of the Internet are open and used by all devices connected to the network

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7 0
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Write java code to create a new class called "student". an object of the student class has attributes like student id, name and
Fiesta28 [93]
Here you go. I added a constructor and a toString overload to make the object creation and printing as easy as possible.

public class student {
    private String _id;
    private String _name;
    private String _address;

    public student(String id, String name, String address) {
        _id = id;
        _name = name;
        _address = address;
    }

    public String toString() {
        return "Id: " + _id + "\nName: " + _name + "\nAddress: "+ _address;
    }

    public static void main(String[] args) {
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8 0
3 years ago
1. Create an anonymous block that will count the number of students whose gr_t1 grade is higher than the average on gr_t1 and di
sweet [91]

Answer:

The Anonymous Block will be:

 1 DECLARE

 2  

 3  lv_grade_row grade%rowtype;

 4  lv_gr_avg grade.gr_t1%type;

 5  lv_std_name varchar2(80);

 6  cursor cursor_grade is select * from grade;

 7

 8  BEGIN

 9

10  select avg(gr_t1) INTO lv_gr_avg from grade;

11  open cursor_grade;

12  fetch cursor_grade INTO lv_grade_row;

13

14  while cursor_grade%found loop

15

16  if

17  lv_grade_row.gr_t1>lv_gr_avg then lv_std_name :=  

lv_grade_row.std_fname|| ' ' ||lv_grade_row.std_lname|| ' ' ||

lv_grade_row.gr_t1;

18  dbms_output.put_line(lv_std_name);

19

20  end if;

21  fetch cursor_grade into lv_grade_row;

22

Explanation:

4 0
3 years ago
16235 to the nearest ten thousand
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16235 to the nearest ten thousand would be 20,000.

Hope this helps :)
~ Davinia.
7 0
3 years ago
Read 2 more answers
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