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Tasya [4]
3 years ago
9

When Russ opened a website on his browser, he saw an error that the site was not compatible with the browser version he was runn

ing it on. What tools could Russ use to troubleshoot this issue?
Computers and Technology
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:

Patch finders.

Explanation:

Once Russ accessed a webpage on his computer, he had seen an issue that the page was not associated with the browser variant on which he was executing it, although it was important to use patch finders tool to fix the following problems because patch finder is only the software that can resolve the following issues.

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Complete each sentence to describe different elements of an Excel worksheet.
barxatty [35]

Answer:

Answer is - cell, - column, - string value

Explanation:

  • <em>Cell - this is often referred to as the intersection of a single row and column.  </em>
  • <em>Column - this is a group of cells which are represented vertically.  </em>
  • <em>String - these are values that are inside the cell which are represented through texts or group of letters including acceptable symbols and characters.</em>
7 0
2 years ago
Read 2 more answers
How to calculate 3 X (50 + 40) ÷ 5 on excel 2016
kozerog [31]

Answer:

I think this might help, don't know much of this

Explanation:

How do you calculate 3.5 increase in Excel?

How To Increase a Number By a Percentage. If want to calculate a percentage increase in Excel (i.e. increase a number by a specified percentage), this can be done by simply multiply the number by 1 + the percentage increase. - which gives the result 60.

8 0
3 years ago
Read 2 more answers
Using recursion, write a program that asks a user to enter the starting coordinates (row, then column), the ending coordinates (
Luden [163]

Answer:

The program in Python is as follows

def Paths(row,col):

if row ==0 or col==0:

 return 1

return (Paths(row-1, col) + Paths(row, col-1))

row = int(input("Row: "))

col = int(input("Column: "))

print("Paths: ", Paths(row,col))

Explanation:

This defines the function

def Paths(row,col):

If row or column is 0, the function returns 1

<em> if row ==0 or col==0: </em>

<em>  return 1 </em>

This calls the function recursively, as long as row and col are greater than 1

<em> return (Paths(row-1, col) + Paths(row, col-1))</em>

The main begins here

This prompts the user for rows

row = int(input("Row: "))

This prompts the user for columns

col = int(input("Column: "))

This calls the Paths function and prints the number of paths

print("Paths: ", Paths(row,col))

4 0
2 years ago
By arranging users into security groups, it is possible to set permissions at a group-level, avoiding the unwieldy alternative o
Anni [7]

Answer:

The department by department is arranging users into security groups to set permission at a group-level.

Explanation:

Team by team is just formed group method but the team been set will work on based on the project. Once the project is getting over then the team group assigned permission has to be disabled or deleted.

 

Department by department is just good methods where each department will have a list of users and easy to assign the group.

user-by-user. is just assigning the rights of each individual user. But if the user has multiple departments login it will be good advice.

organization-by-organization. It is just assigning rights to complete users list in the organization.  

6 0
3 years ago
- Create a Java program in both Windows and Ubuntu using any of their Editors *** DO NOT USE IDE'S SUCH AS ECLIPSE, NETBEANS, ET
Marat540 [252]

Answer:

Following are the code to this question:

public class ArrayMath//defining a class ArrayMath

{

public static void main(String[] args) //defining main method

{

int x[][]=new int[10][10]; //defining a 2D array  

arrays(x);//calling a method arrays by passing an array

}

private static void arrays(int[][] x)//defining a method arrays

{

int odd_column_sum=0,sum_of_Elements=0,i,j,even=1;//defining integer variable  

for(i=0;i<x.length;i++)//defining loop for columns  

{

for(j=0;j<x[0].length;j++)//defining loop for rows

{

x[i][j]=i*j;//multiply the i and j value atore in array

}

}

System.out.println("::The 2D array :: ");//print message

for(i=0;i<x.length;i++)//defining loop for columns

{

System.out.print("\t");//use print method for line space and line break  

for(j=0;j<x[0].length;j++)//defining loop for rows

{

System.out.printf("%d\t",x[i][j]); //print array values

}

System.out.println( );//print for line break

}

for(i=0;i<x.length;i++) //defining loop for Columns

{

for(j=0;j<x[0].length;j++) //defining loop for rows

{

if(even%2!=0)//defining if block for check odd number condition

{

odd_column_sum+=x[j][i];//add odd number of array

}

sum_of_Elements+=x[i][j];//add even number of array

}

even++;//increment even variable value by 1

}

System.out.println("The sum of Odd Columns:"+odd_column_sum);//print odd_column_sum value

System.out.println("The array elements :"+sum_of_Elements);//print sum_of_Elements value

}

}

Output:

please find attached file.

Explanation:

In the above-given code, a class "ArrayMath" is defined, inside the class the main method is declared, which define a 2D array "x", this stores 10 columns and 10 rows and at the last, we call the arrays method by passing an array as a variable.

In the arrays method, integer variable, "odd_column_sum, sum_of_Elements, i, j, and even" is defined, in which variable "i and j" is used in the loop for calculating value, even is used to check odd column and then store its value in the "odd_column_sum" variable, and add whole element value is added into the "sum_of_Elements" variable.

8 0
3 years ago
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