One container is filled with a mixture that is 30% acid. A second container is filled with a mixture that is 50% acid. The secon
d container is 50% larger than the first, and the two containers are emptied into a third container. What percent of acid is the third container?
1 answer:
Answer:
42% acid
Step-by-step explanation:
Suppose that these two storage containers are filled to complete capacity?
That makes the second container have 3 volume parts and the first container having 2 volume parts.
v*(1.50)= (3/2)*v
First Container 2v 30% acid
Second Container 3v 50% acid
The mixture of all of this is in the third container. Two parts plus three parts is 5 parts for the mix volume.
=(2*30+3*50)/5
=210/5
=42
So,
42 % Acid, mixture
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