If tan 3x =<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D" id="TexFormula1" title="\sqrt{x}" alt="\sqrt{x}" align="absmiddle"

$The\ slope-intercept\ form:y=mx+b\\\\f(2)=2\to for\ x=2\to y=2\\f(-6)=6\to for x=-6\to y=6\\\\put\ in\ equation\ of\ the\ line:\\\\ -\left\{\begin{array}{ccc}2=2m+b\\6=-6m+b\end{array}\right\ \ \ |subtract\ sides\ of\ the\ equations\\----------\\.\ \ \ -4=8m\ \ \ \ \ |divide\ both\ sides\ by\ 8\\.\ \ \ \ \boxed{m=-\frac{1}{2}}\\\\put\ m=-\frac{1}{2}\ to\ equation\ 2=2m+b:\\\\2=2\cdot(-\frac{1}{2})+b\\2=-1+b\ \ \ \ |add\ 1\ to\ both\ sides\\\boxed{b=3}\\\\\boxed{\boxed{y=-\frac{1}{2}x+3}}$

$therefore:f(x)=-\frac{1}{2}x+3\Rightarrow f(6)=-\frac{1}{2}\cdot6+3=-3+3=0\\\\Answer:\boxed{f(6)=0}$

5 0

2 years ago

Help Fast Please!!!!!!!!! How can you tell if three positive numbers form a Pythagorean triple?

Fiesta28 [93]

Answer/Step-by-step explanation:

Square all three numbers. If the largest number squared is equal to the sum of the squares of the other two, then the numbers form a Pythagorean triple.

or

Since a Pythagorean triple is three positive integers a, b, and c such that (a^2)+(b^2)=(c^2), first take the sum of the squares of the two legs and make an estimate. For example, 3, 4, and 5 is a Pythagorean triple since 9+16=25

either one works

3 0

2 years ago