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navik [9.2K]
3 years ago
11

Show you work for 1.03 time 1.03

Mathematics
2 answers:
hram777 [196]3 years ago
6 0
1.03 time 1.03 = 1.0609

PolarNik [594]3 years ago
5 0
1.03
1.03
-*------
      3 09
   1  0 3 00
=1.0609

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Find a vector function, r(t), that represents the curve of intersection of the two surfaces. The paraboloid z = 6x2 + y2 and the
LenKa [72]

Answer:

\mathbf{r^{\to} (t) = ti^{\to} + 5t^2^{\to} j+(6t^2 + 25t^4) k ^{\to}}

Step-by-step explanation:

Given that:

The paraboloid surface z = 6x² + y² and the parabolic cylinder y = 5x²

Let assume that:

x = t

then from y = 5x², we have:

y = 5t²

Now replace y = 5t² and x = t into z = 6x² + y²

z = 6t² + (5t²)²

z = 6t² + 25t⁴

Hence, the curve of intersection is illustrated by the set of equations:

x = t, y = 5t², and z = 6t² + 25t⁴

As a vector equation:

\mathbf{r^{\to} (t) = ti^{\to} + 5t^2^{\to} j+(6t^2 + 25t^4) k ^{\to}}

6 0
3 years ago
An elliptical-shaped path surrounds a garden, modeled by quantity x minus 20 end quantity squared over 169 plus quantity y minus
Margaret [11]

The <em>maximum</em> distance between any two points of the ellipse is 34 feet.

<h3>Procedure - Determination of the distance between two points of a ellipse</h3>

The maximum distance between any two points of a ellipse is the <em>maximum</em> distance between the ends of the ellipse along the <em>longest</em> axis, which is parallel to the y-axis in this case.

In addition, the equation of the ellipse in <em>standard</em> form is defined by this formula:

\frac{(x-h)^{2}}{a^{2}} + \frac{(y-k)^{2}}{b^{2}} = 1 (1)

Where:

  • h, k - Coordinates of the center of the ellipse.
  • a, b - Lengths of each semiaxis.

Hence, the maximum distance (d_{max}), in feet, is calculated by this formula:

d_{max} = 2\cdot b (2)

If we know that b = 17, then the maximum distance between any two points of the ellipse is:

d_{max} = 2\cdot (17\,ft)

d_{max} = 34\,ft

The <em>maximum</em> distance between any two points of the ellipse is 34 feet. \blacksquare

<h3>Remark</h3>

The statement is incomplete and poorly formatted, correct form is presented below:

<em>An elliptical-shaped path surrounds a garden, modeled by </em>\frac{(x-20)^{2}}{169} + \frac{(y-18)^{2}}{289} = 1<em>, where all measurements are in feet. What is the maximum distance between any two points of the path.</em>

To learn more on ellipses, we kindly invite to check this verified question: brainly.com/question/19507943

5 0
2 years ago
a rectangular pool has an area of 640 square feet. the is 12 feet shorter than the width. the length of the pool is feet and the
Ray Of Light [21]

Given:

Area of rectangular pool = 640 square feet

The length is 12 feet shorter than the width.

To find:

The length and width of the pool.

Solution:

Let width of the pool = x feet

Then, Length of the pool = (x-12) feet

Area of a rectangle is

Area=length\times width

Area=(x-12)\times x

Area of pool is 640 square feet. So,

(x-12)x=640

x^2-12x-640=0

Splitting the middle term, we get

x^2-32x+20x-640=0

x(x-32)+20(x-32)=0

(x+20)(x-32)=0

Using zero product property, we get

x=-20,32

Dimensions cannot be negative. So, x=32.

Now,

Width of the pool = 32 feet

Length of the pool = 32-12 = 20 feet

Therefore, the length of the pool is 20 feet and width is 32 feet.

7 0
3 years ago
What are the factors for 21 ,40,36,45
Ugo [173]
Hello I can help you with this :)
5 0
3 years ago
Que volumen ocupan 0.8kg de alcohol?¿cual es el peso de este volumen? la densidad del alcohol es 790 kg/m3
telo118 [61]

Respuesta:

Volumen = 0.0010126 m³

Ancho = 7,84 N

Explicación paso a paso:

Dado que:

Masa, m de alcohol = 0,8 kg

Densidad del alcohol, d = 790 kg / m³

Recordar :

Densidad, d = masa, m / volumen, v

Volumen = masa / densidad

Volumen = 0,8 kg / 790 kg / m³

Volumen = 0.0010126 m³

Peso, W = densidad * aceleración debido a la gravedad * volumen

Ancho = 790 * 9,8 * 0,0010126

W = 7.8395

Ancho = 7,84 N

4 0
3 years ago
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