I believe the answer is $144
Because you first have to multiple 8ft*3 ft=24ft then you have to multiply 24ft times $6=$144
Answer:
$37.50
Step-by-step explanation:
If 50 apples cost $25 to find the cost of 1 apple, we divide the total cost by the total number of items. In this case, we do 25/50.
One apple costs 0.50. If we need 75 apples then we simply multiply 0.50 by 75 which gets us 37.50.
The best strategy is to use the tables in this example. The tables will give an exact cost for an exact number of apples or oranges. You can then use these pieces of information to determine which number of apples and oranges will get you closest to $10.
The diagram strategy is not accurate based on the information.
The double bar graph is also not going to work because the two pieces of information are related, so you would not create a separate bar for the price and the number of apples.
Answer:
75 miles
Step-by-step explanation:
We are given the scale on the map, which is that 1 inch is 25 miles in real life. We can write that as a ratio of 1 inch: 25 miles. Now say we have two inches, then we have 50 miles because we add on another 25 miles, then we do that again and we get to 75 miles.
Another way to think about it (more complicated):
you can represent ratios as a fraction
so we do 1/25=3/x
To find x, we can do (25*3)/1 which equals 75, if you don't know what I did there then you don't know, sorry!
you can also do it in a different way
same scenario though
you represent it as a fraction
and do 1/25=3/x. We see that the ratio from 1 to 3 is multiplied by 3 so that means the ratio from 25 to x is also going to be multiplied by 3, and 25 multiplied by 3 is 75.
Please let me know if you have any questions.
Given:
Total number of problems = 24
Michael completed 
of his homework in 
of an hour.
To find:
What fraction of his homework would he complete in one hour.
Solution:
We have,
Part of work done in of an hour 
Part of work done in an hour 
Therefore, he complete 
of his homework in 1 hour. Hence, all options are incorrect.
