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zaharov [31]
3 years ago
13

Write an equation of the line containing the given point and perpendicular to the given line. express your answer in the form y=

mx+b. (8,9); 4x+y=5
Mathematics
1 answer:
katovenus [111]3 years ago
4 0
The given line
4x + y = 5
The slope of the given line is -4

Find the slope of perpendicular line
m₁ × m₂ = -1
-4 × m₂ = -1
m₂ = -1/-4
m₂ = 1/4

Find the equation of perpendicular line
y - y₁ = m(x - x₁)
y - 9 = 1/4(x - 8)
y - 9 = (1/4) x - 2
y = (1/4)x - 2 + 9
y = (1/4)x + 7
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A 4-inch long ribbon is cut into pieces. If the length of each piece is 12of an inch, how many pieces are cut?
vekshin1

Answer:

48 pieces are cut.

Step-by-step explanation:

1/12 of an inch means that one inch would be 12 pieces. Since there are 4 pieces it would be 12x4= 48 pieces.

5 0
3 years ago
Help please I’ll make it brainliest!!!!!
mr Goodwill [35]

Step-by-step explanation:

it is very simple, once you remember that "kilo" means 1000, "mili" means 1/1000, and "centi" means 1/100.

and therefore 1 cg = 10 mg, or 1 cm = 10 mm.

"deci" means 1/10.

and therefore 1 dm = 100 mm, 1dg = 100 mg.

1.

9.32 kg = 9.32×1000 = 9320 g

2.

1.429 g = 1.429/1000 = 0.001429 kg

3.

287 g = 287/1000 = 0.287 kg

4.

4.6 L = 4.6×1000 = 4600 mL

5.

0.119 L = 0.119×1000 = 119 mL

6.

9936 mL = 9936/1000 = 9.936 L

7.

26793 mL = 26793/1000 = 26.793 L

8.

0.06 L = 0.06×1000 = 60 mL

9.

170 cg = 170×10 = 1700 mg

10.

2674 cm = 2674/100 = 26.74 m

11.

9.05 mm = 9.05/100 = 0.0905 dm

12.

2 L = 2×1000 = 2000 mL

13.

62.4 L = 62.4×1000 = 62400 mL

14.

99.9 mm = 99.9/1000 = 0.0999 m

15.

4.34 g = 4.34×100 = 434 cg

16.

10 km = 10×1000 m = 10×1000×1000 = 10000000 mm

17.

65 cL = 65/100 = 0.65 L

18.

105 mL = 105/1000 = 0.105 L

19.

0.27 g = 0.27×100 = 27 cg

20.

7777 m = 7777/1000 = 7.777 km

4 0
1 year ago
Factored form of 16m^4-121
AnnZ [28]

16m^4-121 =(4m^2-11)(4m^2+11)

8 0
2 years ago
30 points plz help me lo links
katen-ka-za [31]

Answer:

(-1/3, 3/4)

Step-by-step explanation:

9x + 8y = 3

6x - 12y = -11

Let's solve the system by eliminating x. We need the coefficients of x to be additive inverses, so they will add to zero eliminating x. The LCM of 9 and 6 is 18. Let's multiply both sides of the first by 2 and both sides of the second equation by -3.

18x + 16y = 6

-18x + 36y = 33

The coefficients of x are 18 and -18, which add to zero. Now we add these two equations.

52y = 39

y = 39/52

y = 3/4

Now we substitute y with 3/4 in the first equation and solve for x.

9x + 8y = 3

9x + 8(3/4) = 3

9x + 6 = 3

9x = -3

x = -3/9

x = -1/3

Solution: (-1/3, 3/4)

4 0
2 years ago
Undefined terms needed to define a line segment
Alenkinab [10]
Is a point line and <span>plane</span>
7 0
3 years ago
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