Answer:
8^5^7
Step-by-step explanation:
Multiply the numbers:
<u>4</u>X^2 y^3 x <u>2</u>x^3 y^4
<u>8</u>^2 ^3 ^3 ^4
Combine Exponents:
8<u>^2</u> ^3 <u>^3</u> ^4
8<u>^5</u> ^3 ^4
8^5 <u>^3</u> <u>^4</u>
8^5 <u>^7</u>
Mark Brainliest please
I think it looks like the image
Answer:
2
Step-by-step explanation:
The height formula given is:
h = -16t^2 + 70
That means the object will be initially (t=0) at the height 70 feet, from where it will be dropped.
If we want to know the time when the object will be at height 6 feet, we just need to use h=6 in the equation, and then calculate the value of t:
6 = -16t^2 + 70
16t^2 = 64
t^2 =4
t = 2 s
So, it will take 2 seconds for the object to be 6 feet above the valley floor.