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STALIN [3.7K]
2 years ago
13

The ratio of Ali's mass to John's mass is 6:5. The ratio of John's muss

Mathematics
1 answer:
djverab [1.8K]2 years ago
5 0

Step-by-step explanation:

The ratio of Ali mass to Williams mass is

6 : 3

= 2 : 1

Option 2 is the correct answer

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Which of the following conditions must be met in order to make a statistical inference about a population based on a sample
klasskru [66]

Answer:

For this case if we want to conclude that  the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:

\bar X \sim (\mu, \frac{\sigma}{\sqrt{n}})

For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:

n>= 30

Step-by-step explanation:

For this case if we want to conclude that  the sample does not come from a normally distributed population we need to satisfy the condition that the sample size would be large enough in order to use the central limit theoream and approximate the sample mean with the following distribution:

\bar X \sim (\mu, \frac{\sigma}{\sqrt{n}})

For this case the condition required in order to consider a sample size large is that n>30, then the best solution would be:

n>= 30

7 0
3 years ago
Ex) A nursery plants a new tree and attaches a guy wire to help support the tree
o-na [289]

Answer:

d =   5,35 ft

Step-by-step explanation: See annex

Figure in  annex is clear,  

sin ∠42⁰  = d / 8

And

sin ∠42⁰   =  0.669

d/8   =  0,669

d  =  0,669*8  

d =   5,35 ft

8 0
3 years ago
Read 2 more answers
What would the variables for a and b be? 3/x + 5/x^2 = (ax+b)/x^2
allsm [11]

Answer:

a=3,b=5

Step-by-step explanation:

\frac{3}{x}  +  \frac{5}{ {x}^{2}  }  \\  =  \frac{3x}{ {x}^{2} }   +  \frac{5}{ {x}^{2} }  \\  =  \frac{3x + 5}{ {x}^{2} }

so as you got it:

\frac{(ax + b)}{ {x}^{2} }  =  \frac{3x + 5}{ {x}^{2} }  \\ a = 3 \\ b = 5

4 0
3 years ago
10m^2 of tiles cover a pool, the pool is shaped as a square, so all four edges are the same, and the depth is constant but not e
nignag [31]
Assume:

Size of sides = x m
Depth of the pool = y m

Therefore, surface area = x^2+4xy =10 m^2

Then, y = (10-x^2)/(4x)

Now,
Volume (V) = x^2*y = x^2*y =x^2(10-x^2)/4x = (10x-x^3)/4 = 1/4(10x-x^3)
For maximum volume, first derivative of volume function is equal to zero.
That is,
dV/dx =0 = 1/4(10-3x^2)
Then,
1/4(10-3x^2) = 0
10-3x^2 = 0
3x^2=10
x= sqrt (10/3) = 1.826 m
And
y= (10-1.826^2)/(4*1.826) = 0.913 m

Therefore,
V= 1.826^2*0.913 = 3.044 m^3
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3 years ago
Compute the probability of random sly selecting a queen or diamond.
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