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jeka57 [31]
3 years ago
11

Lin ran twice as far as Diego. Diego ran 300m farther than jada. Jada ran 1/3 the distance that Noah ran. Noah ran 1200 m. How f

ar did Lin run?
Mathematics
1 answer:
astraxan [27]3 years ago
8 0
Lin ran 1400 meters in total
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What is the value of f(3) in the function f(x)=5/6x+8
natita [175]

For this case we have a function of the form y = f (x), where f (x) = \frac {5} {6} x + 8

We must find the value of the function when x = 3, that is, we must find f (3). So:

f (3) = \frac {5} {6} (3) + 8\\f (3) = \frac {15} {6} +8\\f (3) = \frac {5} {2} +8\\f (3) = 2.5 + 8\\f (3) = 10.5

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1. You are given the 3rd and 5th term of an arithmetic sequence. Describe in words how to determine the general term.
kozerog [31]

Step-by-step explanation:

1. In an arithmetic sequence, the general term can be written as

xₙ = y + d(a-1), where xₐ represents the ath term, y is the first value, and d is the common difference.

Given the third term and the fifth term, and knowing that the difference between each term is d, we can say that the 4th term is x₃+d and the fifth term is the fourth term plus d, or (x₃+d)+d =

x₃+2d. =x₅ Given x₃ and x₅, we can subtract x₃ from both sides to get

x₅-x₃ = 2d

divide by 2 to isolate d

(x₅-x₃)/2 = d

This lets us solve for d. Given d, we can say that

x₃ = y+d(2)

subtract 2*d from both sides to isolate the y

x₃ -2*d = y

Therefore, because we know x₃ and d at this point, we can solve for y, letting us plug y and d into our original equation of

xₙ = y + d(a-1)

2.

Given the third and fifth term, with a common ratio of r, we can say that the fourth term is x₃ * r. Then, the fifth term is

x₃* r * r

= x₃*r² = x₅

divide both sides by x₃ to isolate the r²

x₅/x₃ = r²

square root both sides

√(x₅/x₃) = ±r

One thing that is important to note is that we don't know whether r is positive or negative. For example, if x₃ = 4 and x₅ = 16, regardless of whether r is equal to 2 or -2, 4*r² = 16. I will be assuming that r is positive for this question.

Given the common ratio, we can find x₆ as x₅ * r, x₇ as x₅*r², and all the way up to x₁₀ = x₅*r⁵. We don't know the general term, but can still find the tenth term of the sequence

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