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3 years ago

Evaluate the expression when b=-3 and x = 2 . 6x-b

Mathematics

1 answer:

Rudik [331]3 years ago

6 0

Answer:

Step-by-step explanation:

You have to insert the values for b and x into the formula.

6(2) - (-3)

Then you simplify.

12+3

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How many times larger is 4 × 10^10 than 2 × 10^8?

fgiga [73]

Answer:10

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

3/4 of $530.40 show work

Minchanka [31]

Multiply $530.40 by 3/4. You get the equation
$\frac{530.40 * 3}{4}$
If you simplify this, you get the solution of $397.80

$397.80

4 0

3 years ago

Can you please find the domain and the range

ohaa [14]

Answer:

domain: (-4, ∞)
range: [-4, ∞)

Step-by-step explanation:

The domain is the horizontal extent of the function. This function is defined for all values of x greater than (but not including) -4. Its domain is (-4, ∞).

The range is the vertical extent of the function. This function gives output values of any number greater than or equal to -4. Its range is [-4, ∞).

Interval notation uses square brackets when the value is included in the interval. It uses round brackets (parentheses) when the end value is not included in the interval. ∞ is not a number, so that end always gets a round bracket.

6 0

4 years ago

Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

4 0

2 years ago

Georgette has purchased award plaques for her company’s conference. Each plaque

lara [203]

Answer:

y=1/7.50x+40

Step-by-step explanation:

I doubled checked myself on desmos and it worked. You start at 40$ because you pay that no matter what. For each one they buy the price goes up by 7.50$.

8 0

3 years ago