Pythagorean Theorem<h2>
Verbally:</h2>
Let's say a and b are the legs, and c is the hypotenuse. Then, algebraically, the theorem is,
Well I’m not sure if I’m right:
This is my answer:
1
The given system of equations 4x + 4y = 32 and 3x + 24 = 3y has only one solution
<u>Solution:</u>
Given, system of equations are:
4x + 4y = 32 ---- eqn (1)
3x + 24 = 3y ----- eqn (2)
We have to determine whether the system has one solution, no solution, or infinitely many solutions.
Now let us solve the given system of equations to determine.
Now, eqn (1) can be written as,
4(x + y) = 32
x + y = 8
x = 8 – y
So, substitute "x" value in eqn (2) to get the value of "y"
3(8 – y) + 24 = 3y
24 – 3y + 24 = 3y
48 = 3y + 3y
y = 8
Then, x = 8 – 8 = 0
Hence we got x = 0 and y = 8
Hence, the given system of equations has only one solution (x, y) = (0, 8)
3t+3=-12
Our goal is to isolate t. Subtract 3 from both sides.
3t+3-3=-12-3
3t=-15
Now divide both sides by 3.
3t/3=-15/3
t=-5
Final answer: t=-5