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vodomira [7]
2 years ago
14

It says the set (1,2,3) can help?

Mathematics
1 answer:
Pani-rosa [81]2 years ago
8 0
I think B. 123, 132, 213, 231, 321, and 312
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3(1/2x-1/3)=1-4/5(5x-3/5)
KonstantinChe [14]

Answer:

haha so easy 17272

3 0
3 years ago
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Find the area of the Shaded region below in all of the smaller squares are identical in size
Lelechka [254]

Area of the shaded region = 80 in²

Explanation:

The outer diagram is a square

Area of the square = length × length

length = 12in

Area of the square = 12in × 12in

Area of the square = 144in²

There are 3 smaller squares in each row and column:

The length in each row and colum = 12

the length o fone small box = 12/3 = 4

Area of the smaller box = 4in × 4in = 16 in²

There are 4 boxes unshaded

Area of 4 unshaded boxes = 4 × 16 in² = 64in²

Area of the shaded region = Area of the outer box - area of the unshaded boxes

Area of the shaded region = 144 - 64

Area of the shaded region = 80 in²

7 0
1 year ago
1. Given f(x) = 3x + 7
snow_lady [41]

Step-by-step explanation:

let y=f(x)

y=3x+7 ,then x=3y+7➡️3y=x-7➡️y=(x-7)/3

f'(x)=(x-7)/3

5 0
3 years ago
What is the solution to this equation?
tiny-mole [99]
Hope this helps explain it

7 0
3 years ago
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Simplify the following expressions without using calculator 8/(2sqrt(6) + 3) - 4/(2sqrt(6) -3)​
lesya [120]

Step-by-step explanation:

\tt \longrightarrow \dfrac{8}{2 \sqrt{6}  + 3 }  - \dfrac{4}{2 \sqrt{6}   - 3 }  \\  \\  \tt \longrightarrow \dfrac{8(2 \sqrt{6}  - 3) - 4(2 \sqrt{6}   +  3)}{(2 \sqrt{6}  + 3)(2 \sqrt{6}   - 3 ) }   \\  \\  \tt \longrightarrow \dfrac{16\sqrt{6}  - 24 - 8 \sqrt{6}    - 12}{(2 \sqrt{6} ) {}^{2}   -  (3) {}^{2} } \\  \\ \tt \longrightarrow \dfrac{8\sqrt{6}  - 36}{24   -  9 }  \\  \\   \tt  \green{\longrightarrow \dfrac{8\sqrt{6}  - 36}{15 }}

4 0
3 years ago
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