Create a table of data for two different linear functions. The table should use the same values of x for both functions. Based
1 answer:
<span>A table of data for two different linear functions using the same values of x for both functions is shown below:
</span>![\begin{tabular} {|c|c|c|} x&y=2x+7&y=-x+4\\[1ex] -3&2(-3)+7=-6+7=1&-(-3)+4=3+4=7\\ -2&2(-2)+7=-4+7=3&-(-2)+4=2+4=6\\ -1&2(-1)+7=-2+7=5&-(-1)+4=1+4=5\\ 0&2(0)+7=0+7=7&-(0)+4=0+4=4\\ 1&2(1)+7=2+7=9&-(1)+4=-1+4=3\\ 2&2(2)+7=4+7=11&-(2)+4=-2+4=2\\ 3&2(3)+7=6+7=13&-(3)+4=-3+4=1 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7Cc%7C%7D%0Ax%26y%3D2x%2B7%26y%3D-x%2B4%5C%5C%5B1ex%5D%0A-3%262%28-3%29%2B7%3D-6%2B7%3D1%26-%28-3%29%2B4%3D3%2B4%3D7%5C%5C%0A-2%262%28-2%29%2B7%3D-4%2B7%3D3%26-%28-2%29%2B4%3D2%2B4%3D6%5C%5C%0A-1%262%28-1%29%2B7%3D-2%2B7%3D5%26-%28-1%29%2B4%3D1%2B4%3D5%5C%5C%0A0%262%280%29%2B7%3D0%2B7%3D7%26-%280%29%2B4%3D0%2B4%3D4%5C%5C%0A1%262%281%29%2B7%3D2%2B7%3D9%26-%281%29%2B4%3D-1%2B4%3D3%5C%5C%0A2%262%282%29%2B7%3D4%2B7%3D11%26-%282%29%2B4%3D-2%2B4%3D2%5C%5C%0A3%262%283%29%2B7%3D6%2B7%3D13%26-%283%29%2B4%3D-3%2B4%3D1%0A%5Cend%7Btabular%7D)
From the table, it can be seen that when x = -1, the function y = 2x + 7 has a value of 5 and the function y = -x + 4 has a value of 5.
Therefore, the graph of the two functions will intercect at (1, 5)
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From the table, it can be seen that when x = -1, the function y = 2x + 7 has a value of 5 and the function y = -x + 4 has a value of 5.
Therefore, the graph of the two functions will intercect at (1, 5)
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Answer:
The expression used to find the change in temperature per hour is Algebraic expression
Thus per hour; the temperature falls at the rate of
Step-by-step explanation:
A temperature falls from 0 to in
Which expression finds the change in temperature per hour.
From the above given information;
The initial temperature is 0
The final temperature is
The change in temperature is
Thus;
-12.25 ° = 3.5 hours
To find the change in x° per hour; we have;
x° = 1 hour
The expression used to find the change in temperature per hour is Algebraic expression
From above if we cross multiply ; we have;
(- 12.25° × 1 hour) = (x° × 3.5 hour)
Divide both sides by 3.5 hours; we have:
x° = - 3.5
x° =
Thus per hour; the temperature falls at the rate of
Answer:
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Step-by-step explanation:
