1. Let the sides of a triangle be a, b and c.
Assume c is the largest side.
The maximum angle measure in an acute triangle can be 90°. In such a case we would have
Now forget about side c, and open the angle between a and b just a little bit. Now clearly
is larger that
because the "new c" is larger than the old one.
2. So for 3 numbers to be the lengths of the sides of an acute triangle, the sum of the squares of the 2 smaller numbers must be at most equal to the square of the largest number but not more.
Check:
A. 4^2+5^2=16+25=41<49
B. 5^2+7^2=25+49=74>64
C. 6^2+7^2=36+49=85<100
D. 7^2+9^2=49+81=130<144
3. Correct answer: only B
Answer:
..................................
If i’m seeing correctly, the cursor is covering a number for the measure of angle BCD. assuming that ABE is the same, as it looks, then it should be the number your cursor is covering.
The answer will be -3p -4